Answer:
Explanation:
Given:
mass of first particle,
mass of second particle,
mass of third particle,
coordinate position of first particle in meters,
coordinate position of second particle in meters,
coordinate position of third particle in meters,
<u>Now, gravitational force on particle 3 due to particle 1:</u>
towards positive Y axis.
<u>gravitational force on particle 3 due to particle 2:</u>
towards positive X axis.
<u>Now the net force</u>
<em>For angle in counterclockwise direction from the +x-axis</em>
Answer:
r = 3.787 10¹¹ m
Explanation:
We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration
F = ma
G m M / r² = m a
The centripetal acceleration is given by
a = v² / r
For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship
v = d / t
The distance traveled Esla orbits, in a circle the distance is
d = 2 π r
Time in time to complete the orbit, called period
v = 2π r / T
Let's replace
G m M / r² = m a
G M / r² = (2π r / T)² / r
G M / r² = 4π² r / T²
G M T² = 4π² r3
r = ∛ (G M T² / 4π²)
Let's reduce the magnitudes to the SI system
T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)
T = 1.03 10⁸ s
Let's calculate
r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]
r = ∛ (21.44 10³⁵ / 39.478)
r = ∛(0.0543087 10 36)
r = 0.3787 10¹² m
r = 3.787 10¹¹ m
BEING HONEST , OPTIMISTIC,DISCIPLINED, PUNCTUAL ,TRUTHFUL AND GOOD ORATOR(SPEAKER) , AND HOPEFUL ARE OTHER BASIC QUALITIES AN EFFECTIVE LEADER MUST POSSESS. ALSO,HE MUST NEVER DIFFERENCE BETWEEN ANY OF HIS FOLLOWERS OR DO PARTIALLY AT ANY TIME . HE SHOULD TREAT EVERY ONE EQUALLY.
Explanation:
Sound travels fastest in solids,than liquids, and faster in liquids, than in gases.
Answer:
196000 N
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Area (A) = 2 m²
Force (F) =.?
Next, we shall determine the pressure in the tank.
This can be obtained as follow:
P = dgh
Where
P is the pressure.
d is the density of the liquid.
g is acceleration due to gravity
h is the height.
Height (h) = 10 m
Density (d) of water = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Pressure (P) =...?
P = dgh
P = 1000 × 9.8 × 10
P = 98000 N/m²
Therefore, the pressure acting on the tank is 98000 N/m²
Finally, we shall determine the force of gravity acting on the column of water as follow:
Area (A) = 2 m²
Pressure (P) = 98000 N/m²
Force (F) =.?
Pressure (P) = Force (F) /Area (A)
P = F /A
98000 = F/ 2
Cross multiply
F = 98000 × 2
F = 196000 N
Therefore, the force of gravity acting on the column of water is 196000 N