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3 years ago

About how long does it take Earth to complete one revolution around the Sun?

Physics

2 answers:

Marysya12 [62]3 years ago

8 0

1 year……………................

SSSSS [86.1K]3 years ago

4 0

Answer:

1 year = 365 days

because Earth Revolution is the movement of the Earth around the Sun

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A closed system consists of 0.3 kmol of octane occupying a volume of 5 m3 . Determine

Alenkinab [10]

Answer:

(a). The weight of the system is 336.32 N.

(b). The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

Explanation:

Given that,

Weight of octane = 0.3 kmol

Volume = 5 m³

(a). Molecular mass of octane

$M=114.28\ g/mol$

We need to calculate the mass of octane

Mass of 0.3 k mol of octane is

$M=114.28\times0.3\times1000$

$M=34.284\ kg$

We need to calculate the weight of the system

Using formula of weight

$W=mg$

Put the value into the formula

$W=34.284\times9.81$

$W=336.32\ N$

(b). We need to calculate the molar volume

Using formula of molar volume

$\text{molar volume}=\dfrac{volume}{volume of moles}$

Put the value into the formula

$\text{molar volume}=\dfrac{5}{0.3}$

$\text{molar volume}=16.6\ m^3/k mol$

We need to calculate the mass based volume

Using formula of mass based volume

$\text{mass based volume}=\dfrac{volume}{mass}$

Put the value into the formula

$\text{mass based volume}=\dfrac{5}{34.284}$

$\text{mass based volume}=0.145\ m^3/kg$

Hence, (a). The weight of the system is 336.32 N.

(b). The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

3 0

3 years ago

A 6.0-kg block slides from point A down a frictionless curve to point B. After the block passes point B, a friction force oppose

konstantin123 [22]

Answer: B. 0.40

Explanation:

6 0

3 years ago

Read 2 more answers

A bucket weighing 5 lbs is lifted at a constant rate from the bottom of a 100 ft well by a rope which weighs 5 lbs. The bucket h

8_murik_8 [283]

Answer:

$W_{bucket} = 24934.85\,lbf\cdot ft$

Explanation:

The system is modelled after the Principle of Energy Conservation and the Work-Energy Theorem:

$W_{bucket} = U_{g,B, bucket} - U_{g,A,bucket} +U_{g, B, water}-U_{g,A,water} +U_{g, B, rope} -U_{g,A,rope}$

$W_{bucket} = (5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-0\,ft) + (25\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft) - (30\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (0\,ft)+(5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-50\,ft)$

$W_{bucket} = 24934.85\,lbf\cdot ft$

6 0

4 years ago

A student moves a 1.50 kg book from a shelf 2.00 meters high to a shelf 1.20 meters high.

MAVERICK [17]

Answer:

17.64 j

Explanation:

thats the answer.

6 0

3 years ago

How do you write 0.345 in scientific notation?

GenaCL600 [577]

Answer;

3.45 × 10^-1

Explanation;

-Here we wish to write the number 0.345 as a coefficient times 10 raised to an exponent. To convert to scientific notation, start by moving the decimal place in the number until you have a coefficient between 1 and 10; here it is 3.45.

-The number of places to the left that you had to move the decimal point is the exponent.

= 0.345

= 3.45/10

= 3.45 × 10^-1

6 0

3 years ago