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Elena L [17]
3 years ago
9

A bicycle wheel rotates uniformly through 2.0 revolutions in 4.0 s. what is the frequency of the wheel's rotation?

Physics
2 answers:
muminat3 years ago
8 0
<span>The frequency is defined as the number of cycles done in one second:
</span>f= \frac{N}{t}<span>
where N is the number of cycles and t is the time taken to complete N cycles. The wheel in this problem does N=2 revolutions in a time of t=4.0s, therefore its frequency of rotation is: 
</span>f= \frac{N}{t} = \frac{2.0}{4.0s}  = 0.5 Hz<span>
</span>
Alex17521 [72]3 years ago
8 0

Answer: The frequency of the wheel's rotation is 0.5 Hz.

Explanation:

Frequency of rotation: It is defined as the number of revolution in a second.

The expression for the frequency in terms of the number of revolution in a given time is as follows;

f=\frac{N}{t}

Here N is the number of cycles and t is the time taken.

Put N= 2 rev and t= 4 s in the above expression.

f=\frac{2}{4}

f=0.5 Hz

Therefore, the correct answer is 0.5 Hz.

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A box has the dimensions of 50 cm × 30 cm × 15 cm, weighs 150 N, and is to be
nadezda [96]

The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

<h3>What is pressure?</h3>

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The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

            = 50 × 30

            = 1500 cm²

Pressure A = 150/1500

                  = 0.1 N/cm³

                    0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

            = 30 × 15

            = 450 cm²

Pressure A = 150/450

                  = 0.3 N/cm³

                    0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

            = 50 × 15

            = 750 cm²

Pressure A = 150/750

                  = 0.2 N/cm³

                    0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

Learn more about Pressure

brainly.com/question/945436

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