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3 years ago

14

A cart was allowed to roll down a ramp from rest. It reached the bottom of the ramp with a speed of 25 cm/s. A student could con

clude that the cart

1 answer:

ladessa [460]3 years ago

4 0

Answer:

A student could conclude that the cart gained momentum as it rolled down.

Explanation:

If the cart was allowed to roll down the ramp from rest, it means that the initial velocity of the cart is zero (0). Also, if the final velocity of the cart became 25 cm/s, it means that the velocity of the cart increased from 0 to 25 cm/s.

Therefore, A student could conclude that the cart gained momentum as it rolled down.

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A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

8 0

4 years ago

In 1991 at smith college, in massachusetts, ferdie adoboe ran 1.00 × 102 m backward in 13.6 s. suppose it takes adoboe 2.00 s to

Alik [6]

as it is given that it covers a total distance 1 * 10^2 m

total time taken by it = 13.6 s

now the average speed is given as ratio of total distance and total time

$v = \frac{d}{t}$

$v = \frac{1* 10^2 }{13.6}$

$v = 7.35 m/s$

so the average speed will be 7.35 m/s

now if it starts from rest and achieve the final speed as 7.35 m/s

now we can use kinematics

$v_f = v_i + at$

$7.35 = 0 + a* 2$

$a = 3.68 m/s^2$

so its acceleration will be 3.68 m/s^2

4 0

4 years ago

A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp

Fantom [35]

Answer:

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = $F/A$ = (ρhAg)/A Where P is pressure

We get

P = ρhg

since g = 9.8 m/s and h is given that is 75m and ρ = $1000 kg/m^3$

so

P = (9.8 m/s)( $1000 kg/m^3$ )(75) we get

P = 735000 Pa

6 0

4 years ago

A woman does 236 J of work

Ratling [72]

Answer:

The woman's force was directed 59.22⁰ to the horizontal.

Explanation:

Given;

work done by the woman, W = 236 J

distance through the load was moved, d = 24.4 m

applied force, F = 18.9 N

inclination of the force, = θ

The work done by the woman is calculated as;

W = Fdcosθ

$cos \ \theta = \frac{W}{Fd} \\\\cos \ \theta = \frac{236 }{18.9 \times 24.4} \\\\cos \ \theta = 0.5118\\\\\theta = cos^{-1} ( 0.5118)\\\\\theta =59.22^0$

Therefore, the woman's force was directed 59.22⁰ to the horizontal.

8 0

3 years ago

Nina is working with electricity and shortens the wires through which the current is flowing. What is Nina most likely trying to

wariber [46]

The answer is D i took the test but got it wrong but i got to see the answers

6 0

3 years ago

Read 2 more answers