Answer:
Angular velocity:
Linear velocity:
Explanation:
When he swings he es ina a circular movement with radius 5.2m. To maintain this circular movement at any time there must be total force on Tarzan equal to the centripetal force:
where m is his mass, r the radius and w the angular velocity. At the lowest point on Tarzan there are two forces acting, gravity and the rope tension, this rope tension equals the force on Tarzan arms:
Where T is the tension on his arms, and W the weigth calculated as:
Where g is the acceleration of gravity. replacing this and remembering that the total force must equal the centripetal force:
Solving for w:
To get the linear velocity at this point:
The answer is Absorb I’m pretty sure.
Answer:
Explanation:
If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m
If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;
Vt = change in distance/time
Vt = 1.5m/5.4s
Vt = 0.28m/s
Note that the Styrofoam reaches its final velocity when the acceleration is zero.
To get the constant value B from the equation a = g-Bv
a = 0m/s²
g = 9.81m/s²
v = 0.28m/s
Substituting the parameters into the formula.
0 = 9.81-0.28B
-9.81 = -0.28B
Divide both sides by -0.28
B = -9.81/-0.28
B = 35.04
b) at t = 0sec, the initial terminal velocity is also zero.
Substituting v = 0 into the equation to get the acceleration.
a = g-Bv
a = g-B(0)
a = g
Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²
c) Given speed v = 0.150m/s
g = 9.81m/s²
B = 35.04
Substituting the given data into the equation a = g-Bv
a = 9.81-35.04(0.15)
a = 9.81 - 5.26
a = 4.55m/s²
Answer:at an angle 
North of east
Explanation:
Given
Velocity of Wind 
Velocity of bee relative to wind 
In vector Form
To get the final velocity in North cos component of 
will balance velocity of wind
Therefore Final velocity is 8.33sin(36.77)=4.98 m/s due to North
at an angle North of east
