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Morgarella [4.7K]
3 years ago
10

“Why can I sometimes see the moon during the day?“Why can I sometimes see the moon during the day?

Physics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

its bc of the way earth spins

Explanation:

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Tarzan plans to cross a gorge by swinging in an arc from a hanging vine. If his arms are capable of exerting a force of 1420 N o
olga_2 [115]

Answer:

Angular velocity:

w=1.2/s

Linear velocity:

v=6.24m/s

Explanation:

When he swings he es ina a circular movement with radius 5.2m. To maintain this circular movement at any time there must be total force on Tarzan equal to the centripetal force:

F_{cent}=m*r*w^{2}

where m is his mass, r the radius and w the angular velocity. At the lowest point on Tarzan there are two forces acting, gravity and the rope tension, this rope tension equals the force on Tarzan arms:

F_{tot}=T-W

Where T is the tension on his arms, and W the weigth calculated as:

W=m*g

Where g is the acceleration of gravity. replacing this and remembering that the total force must equal the centripetal force:

F_{tot}=T-m*g

F_{cent}=m*r*w^{2}=T-m*g

Solving for w:

w=\sqrt{\frac{T/m-g}{r}}=\sqrt{\frac{1420N/81.9kg-9.8m/s^{2}}{5.2m}}=1.2/s

To get the linear velocity at this point:

v=w*r=1.2/s*5.2m=6.24m/s

6 0
3 years ago
Thermal is to heat as ___ is to water.<br> drain<br> waste<br> dilute<br> absorb
alexgriva [62]
The answer is Absorb I’m pretty sure.
5 0
2 years ago
Read 2 more answers
A small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground. Until it reaches terminal speed
goldenfox [79]

Answer:

Explanation:

If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m

If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;

Vt = change in distance/time

Vt = 1.5m/5.4s

Vt = 0.28m/s

Note that the Styrofoam reaches its final velocity when the acceleration is zero.

To get the constant value B from the equation a = g-Bv

a = 0m/s²

g = 9.81m/s²

v = 0.28m/s

Substituting the parameters into the formula.

0 = 9.81-0.28B

-9.81 = -0.28B

Divide both sides by -0.28

B = -9.81/-0.28

B = 35.04

b) at t = 0sec, the initial terminal velocity is also zero.

Substituting v = 0 into the equation to get the acceleration.

a = g-Bv

a = g-B(0)

a = g

Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²

c) Given speed v = 0.150m/s

g = 9.81m/s²

B = 35.04

Substituting the given data into the equation a = g-Bv

a = 9.81-35.04(0.15)

a = 9.81 - 5.26

a = 4.55m/s²

7 0
3 years ago
Read 2 more answers
A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.
4vir4ik [10]

Answer:at an angle 36.77^{\circ} North of east

Explanation:

Given

Velocity of Wind (v_w)=6.68 m/s

Velocity of bee relative to wind (v_{bw})=8.33 m/s

In vector Form

\vec{v_w}=-6.68\hat{i}

\vec{v_{bw}}=8.33(cos\theta \hat{i}+sin\theta \hat{j})

To get the final velocity in North cos component of v_{bw} will balance velocity of wind

8.33\cos \theta =6.68

cos\theta =0.801

\theta =36.77^{\circ}

Therefore Final velocity is 8.33sin(36.77)=4.98 m/s due to North

at an angle 36.77^{\circ} North of east

5 0
3 years ago
In the system you're inspecting the damper motor isn't working, You decide to see if the damper-postion sensor us sending the pr
stiks02 [169]

Answer:

C guys

Explanation:

8 0
3 years ago
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