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devlian [24]
3 years ago
7

10 POINTS BE FAST

Physics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

I think it's c or A hopes this help

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The primary coil of a transformer contains 100 turns; the secondary has 200 turns. the primary coil is connected to a size-aa ba
seropon [69]
Since transformers use laws that require time changing quantities (alternating current), the battery would produce no voltage on the secondary windings. In fact the primary winding would short out the battery to a large extent since the resistance of its copper windings would be very low.
In reality, as the battery was first connected to the primary, a very short blip of voltage would appear on the secondary as the magnetic field initially grew in the core (that would constitute a time-changing magnetic field required for the device to work). But it would immediately go away afterwards and that output cannot be determined without actually doing the experiment due to so many unknowns.
But this question isn't looking for that explanation. It's kind of a trick question.
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Jonas and his family are moving to another part of the city. As Jonas, his brother, and his Dad were driving one of the trucks f
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Answer:newtons second law

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To get something to accelerate you have to apply a pull force . if the mass increase a grater pull is required

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In what sense is the earth a closed system?
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Answer:D

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The strong crystal structure of an ionic compound is one of the main reasons why ionic compounds have a __________ melting point
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The answer is a because it has a high melting tolerance 
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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
Sunny_sXe [5.5K]

Answer:

a) 5.09 seconds

b) 107.07 meters

Explanation:

a) As we know

t_2- t_1 = \sqrt{\frac{2 X}{a} }

Substituting the given values we get

t_2 - t_1 = \sqrt{\frac{2 * 52}{4} } \\t_2 - t_1 = 5.09

It takes 5 .09 s for the motorcycle to accelerate until it catches up with the car

b)

X_{t`2} = v_i \sqrt{\frac{2X}{a} } + 0.5 a\sqrt{\frac{2X}{a} }\\X_{t`2} =  (v_i + 0.5 a) \sqrt{\frac{2X}{a} }\\X_{t`2} =  ( 19 + 2)  \sqrt{\frac{2* 52}{4} }\\X_{t`2} =  21 * 5.09\\X_{t`2} = 107.07

4 0
3 years ago
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