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Bumek [7]
3 years ago
12

3) Choose the best answer.

Physics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

what?

Explanation:

write it correctly I don't understand the question

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A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work
nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

Q:Heat (J)

Delta U: Changes in internal Energy (J)

W:Work (J)

We can plug in the give numbers, Q and W.

Delta U = 658J - 178J = 480J

6 0
3 years ago
A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled
topjm [15]

average velocity is vector displacement / time

time is "almost exactly one hour"

disp = -10m

v= -10/1x60x60 = -1/360m/s

5 0
3 years ago
You're driving a vehicle of mass 1350 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 71 m
sergey [27]

Answer:

v=12.65\ m.s^{-1}

Explanation:

Given:

  • mass of vehicle, m=1350\ kg
  • radius of curvature, r=71\ m
  • coefficient of friction, \mu=0.23

<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>

m.\frac{v^2}{r} =\mu.N

where:

\mu= coefficient of friction

N= normal reaction force due to weight of the car

v= velocity of the car

1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)

v=12.65\ m.s^{-1} is the maximum velocity at which the vehicle can turn without skidding.

5 0
3 years ago
A girl throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s, and it bounc
erma4kov [3.2K]

Answer:

F = 800N

the magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Applying the impulse-momentum equation;

Impulse = change in momentum

Ft = m∆v

F = (m∆v)/t

Where;

F = force

t = time

m = mass

∆v = v2 - v1 = change in velocity

Given;

m = 0.80 kg

t = 0.050 s

The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed.

v2 = 25 m/s

v1 = -25 m/s

∆v = v2 - v1 = 25 - (-25) m/s = 25 +25 = 50 m/s

Substituting the values;

F = (m∆v)/t

F = (0.80×50)/0.05

F = 800N

the magnitude of the average force exerted on the wall by the ball is 800N

4 0
3 years ago
Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are
adelina 88 [10]

Answer:

The final temperature of the two objects is the same.

Explanation:

The expression for the heat energy in terms of mass, specific heat and the change in the temperature is as follows:

Q=mc(T_{f} -T_{i})

Here, Q is the heat energy, m is the mass of the object, c is the specific heat and T_{f},T_{i} are the final temperature and initial temperature.

According to the given question, Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are added to each object.

Q=mc(T_{f}-T_{i})                                             ............(1)

Q=mc(T'_{f}-T_{i})                                            .............(2)

From (1) and (2),

mc(T_{f}-T_{i})=mc(T'_{f}-T_{i})

T_{f}-T_{i}=T'_{f}-T_{i}

T_{f}=T'_{f}

Therefore, the final temperature of the two objects is the same.

6 0
3 years ago
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