Answer:
8.505 m
Explanation:
Let V1 and V2 be velocities of puck A and B respectively
Since A and B move in the same direction, so the relative velocity will be V1+V2=3.5+3.9=7.4m/s
Or
Vr=7.4 m/s
Distance=S= 18 m
Time =t=?
S=Vr×t
==> t=S/Vr
==> t= 18/7.4=2.43 sec
At this time both will strike together
<em><u>Distance by puck A</u></em>
<em>V1=3.5 m/s</em>
Time=t= 2.43 sec
Distance covered=d=?
d=V1×t=3.5×2.43=8.505 m
So, puck A will cover 8.505 meters before collision
Answer:
The answer you would be looking for is A.
Explanation:
Weight of the object is given as

so weight of the object will be maximum where gravity(g) will be maximum
so here out of all given four the gravity "g" will be maximum at the surface of SUN as we know that sun will be of maximum mass out of all four planets
as we know that

so correct answer will be
3. SUN