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2 years ago

6

What is the correct answer?

1 answer:

alina1380 [7]2 years ago

8 0

Answer:

4

Explanation:

I added all of them and them minus the 5.

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Explain what kind of heat transfer occurs when you burn yourself on a hot car seat in the summer.

liubo4ka [24]

Conduction is a mode of transfer of heat there

6 0

3 years ago

How would you obtain a mean value for the specific heat<br> capacity of a material?

lidiya [134]

The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

8 0

2 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,

Studentka2010 [4]

Answer:

Second Trial satisfy principle of conservation of momentum

Explanation:

Given mass of ball A and ball B $=\ 1.0\ Kg.$

Let mass of ball $A$ and $B\ is\ m$

Final velocity of ball $A\ is\ v_1$

Final velocity of ball $B\ is\ v_2$

initial velocity of ball $A\ is\ u_1$

Initial velocity of ball $B\ is\ u_2$

Momentum after collision $=mv_1+mv_2$

Momentum before collision $= mu_1+mu_2$

Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.

Now, $mu_1+mu_2=mv_1+mv_2$

Plugging each trial in this equation we get,

First Trial

$mu_1+mu_2=mv_1+mv_2\\1(1)+1(-2)=1(-2)+1(-1)\\1-2=-2-1\\-1=-3$

momentum before collision $\neq$ moment after collision

Second Trial

$mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1.5)=1(-.5)+1(-.5)\\.5-1.5=-.5-.5\\-1=-1$

moment before collision $=$ moment after collision

Third Trial

$mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1$

momentum before collision $\neq$ moment after collision

Fourth Trial

$mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1)=1(1.5)+1(-1.5)\\.5-1=1.5-1.5\\-.5=0$

momentum before collision $\neq$ moment after collision

We can see only Trial- 2 shows the conservation of momentum in a closed system.

4 0

3 years ago

Read 2 more answers

The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis

Ivan

Answer:

2.08 s

Explanation:

We are given that

Speed,v=50mph=73.3ft/s

1 mile=5280 feet

1 hour=3600 s

Distance,d=461 ft

t=2.5 s

v'=60 mph=88 ft/s

We have to find the perception reaction time.

Perception reaction distance= $d_p=vt=73.3\ti es 2.5=183.25 feet$

$d_p=d'_p$

$d'_p=v't$

$t'=\frac{183.25}{88}=2.08 s$

4 0

3 years ago

A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e

balandron [24]

Answer:

0.00001 J

Explanation:

$k.e = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2} \\ = 0.00001j$

3 0

3 years ago