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Yuri [45]
3 years ago
13

Identify the different engineering activities/steps in the engineering design process for each steps,summarize in 1–3 sentences

what happens during the step?
Engineering
1 answer:
Serggg [28]3 years ago
4 0

Answer:Generate conc epts

Explanation:

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Calculate the amount of current flowing through a 75-watt light bulb that is connected to a 120-volt circuit in your home.
vodomira [7]

Answer:

I = 0.625 A

Explanation:

Given that,

Power of the light bulb, P = 75 W

Voltage of the circuit, V = 120 V

We need to find the current flowing through it. We know that, Power is given by :

P=V\times I

I is the electric current

I=\dfrac{P}{V}\\\\I=\dfrac{75\ W}{120\ V}\\\\I=0.625\ A

So, the current is 0.625 A.

5 0
3 years ago
A piston-cylinder device contains 1.329 kg of nitrogen gas at 120 kPa and 27 degree C. The gas is now compressed slowly in a pol
Shtirlitz [24]

Answer:-0.4199 J/k

Explanation:

Given data

mass of nitrogen(m)=1.329 Kg

Initial pressure\left ( P_1\right )=120KPa

Initial temperature\left ( T_1\right )=27\degree \approx 300k

Final volume is half of initial

R=particular gas constant

Therefore initial volume of gas is given by

PV=mRT

V=0.986\times 10^{-3}

Using PV^{1.49}=constant

P_{1}V^{1.49}=P_2\left (\frac{V}{2}\right )

P_2=337.066KPa

V_2=0.493\times 10^{-3} m^{3}

and entropy is given by

\Delta s=C_v \ln \left (\frac{P_2}{P_1}\right )+C_p \ln \left (\frac{V_2}{V_1}\right )

Where, C_v=\frac{R}{\gamma-1}=0.6059

C_p=\frac{\gamma R}{\gamma -1}=0.9027

Substituting values we get

\Delta s=0.6059\times\ln \left (\frac{337.066}{120}\right )+0.9027 \ln \left (\frac{1}{2}\right )

\Delta s=-0.4199 J/k

4 0
3 years ago
Thank you,Thank you udahfsdf
Degger [83]

Answer: Um, a little feedback would help, cause I'm new but if you are thanking someone, let me know and i'll thank them for you, any other questions?

Explanation:

3 0
3 years ago
About ceramics: Generally are hard and brittle. a) True b)-False
aniked [119]

Answer:

true

Explanation:

8 0
3 years ago
A positively charged electric has a charge of 2 Coulombs. If 12.5x10^18 free electrons are added to it, what will be the net cha
vitfil [10]

The net charge on the said dielectric is 0

1C = 6.25 * 10¹⁸ electrons; hence:

-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))

-12.5x10¹⁸ free electrons = -2 C

A positively charged electric has a charge of 2 Coulombs, hence:

Q₁ = 2C

12.5x10¹⁸ free electrons are added to it, hence:

Q₂ = -2C

Net\ charge(Q_{net})=Q_1+Q_2=2C+(-2C)=0

Hence the net charge on the said dielectric is 0

Find out more at: brainly.com/question/10464929

3 0
3 years ago
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