Answer: 33.35 minutes
Explanation:
A(t) = A(o) *(.5)^[t/(t1/2)]....equ1
Where
A(t) = geiger count after time t = 100
A(o) = initial geiger count = 400
(t1/2) = the half life of decay
t = time between geiger count = 66.7 minutes
Sub into equ 1
100=400(.5)^[66.7/(t1/2)
Equ becomes
.25= (.5)^[66.7/(t1/2)]
Take log of both sides
Log 0.25 = [66.7/(t1/2)] * log 0.5
66.7/(t1/2) = 2
(t1/2) = (66.7/2 ) = 33.35 minutes
Answer:
Your hazard lights warn other drivers of an emergency situation you may be encountering. All four turn signal lights come on when you activate your hazard lights.
Explanation:
on the internet.
Answer:
efficiency of the engine is 0.4167
Explanation:
given data
T high = 1200 K
T low = 700 K
solution
we get here efficiency that is express as
efficiency = 
.........................1
put here value of both temperature we get efficiency
efficiency = 1 - 
efficiency = 1 - 0.58333
efficiency = 0.4167
so efficiency of the engine is 0.4167
Answer:The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.
Explanation:
The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.
Answer:
304.13 mph
Explanation:
Data provided in the question :
The Speed of the flying aircraft = 300 mph
Tailwind of the true airspeed = 50 mph
Now,
The ground speed will be calculated as:
ground speed = 
or
The ground speed = 
or
The ground speed = 304.13 mph
Hence, the ground speed is 304.13 mph
