A positively charged electric has a charge of 2 Coulombs. If 12.5x10^18 free electrons are added to it, what will be the net cha
1 answer:
The net charge on the said dielectric is 0
1C = 6.25 * 10¹⁸ electrons; hence:
-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))
-12.5x10¹⁸ free electrons = -2 C
A positively charged electric has a charge of 2 Coulombs, hence:
Q₁ = 2C
12.5x10¹⁸ free electrons are added to it, hence:
Q₂ = -2C
Hence the net charge on the said dielectric is 0
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Attached below is the detailed solution
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5.6 mm
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Given that:
A cylindrical tank is required to contain a:
Gage Pressure P = 560 kPa
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The inner diameter of the tank = 3 m
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Making thickness t the subject; we have
t = 0.0056 m
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From the above circumferential stress and longitudinal stress; the stress with the higher value will be considered ; which is circumferential stress and it's minimum value with the maximum thickness = 5.6 mm