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SVETLANKA909090 [29]
3 years ago
14

A positively charged electric has a charge of 2 Coulombs. If 12.5x10^18 free electrons are added to it, what will be the net cha

rge on the said dielectric?
Engineering
1 answer:
vitfil [10]3 years ago
3 0

The net charge on the said dielectric is 0

1C = 6.25 * 10¹⁸ electrons; hence:

-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))

-12.5x10¹⁸ free electrons = -2 C

A positively charged electric has a charge of 2 Coulombs, hence:

Q₁ = 2C

12.5x10¹⁸ free electrons are added to it, hence:

Q₂ = -2C

Net\ charge(Q_{net})=Q_1+Q_2=2C+(-2C)=0

Hence the net charge on the said dielectric is 0

Find out more at: brainly.com/question/10464929

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INCLUDE Irvine32.inc

.data

msgIntro  byte "This is Your Name's fourth assembly extra credit program. Will randomly",0dh,0ah

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main PROC

;

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       call Crlf                ;endl

       call WaitMsg             ;pause message

       call Clrscr              ;clear screen

       call Randomize           ;seed the random number generator

       mov edx, OFFSET msgOutput;line of text

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       L1:;//(Loop - Display Text 20 Times)

       call setRanColor         ;calls random color procedure

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main ENDP

;--

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;

; Selects a color with the following probabilities:

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; Receives: nothing

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       mov eax, blue            ;set text blue

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       .ENDIF                   ;end statement

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