Question

A positively charged electric has a charge of 2 Coulombs. If 12.5x10^18 free electrons are added to it, what will be the net charge on the said dielectric?

Answer 1

The net charge on the said dielectric is 0

1C = 6.25 * 10¹⁸ electrons; hence:

-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))

-12.5x10¹⁸ free electrons = -2 C

A positively charged electric has a charge of 2 Coulombs, hence:

Q₁ = 2C

12.5x10¹⁸ free electrons are added to it, hence:

Q₂ = -2C

$Net\ charge(Q_{net})=Q_1+Q_2=2C+(-2C)=0$

Hence the net charge on the said dielectric is 0

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