In unicorns, a heterozygous would have a rainbow tail

How many moles of h+ ions are present in 2.8 l of 0.25 m hydrobromic acid solution?

Romashka [77]

0.7 mol of H⁺ ions are present in 2.8 l of 0.25 m hydrobromic acid solution.

Hydrobromic acid is a strong acid, we can assume that all acid molecules dissociate completely to yield H+ ions and dissociated anion.

<h3>The equation for the dissociation of HBr :</h3>

Hbr <em>(s) → </em>H⁺ <em>(aq) </em>+ Br⁻<em> (aq)</em>

moles H⁺ = ( $2800ml$ ) ( $\frac{1L}{1000ML}$ ) ( $\frac{0.25 mol Hbr}{L}$ ) ( $\frac{1 mol H}{1 mol Hbr}$ )

= 0.7 mol

Therefore, 0.7 mol of H⁺ ions is present.

Learn more about H⁺ ions here:

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4 0

2 years ago

The decomposition of ethanol (C2H5OH) on an alumina (Al2O3) surface C2H5OH1 g2 h C2H4 1 g2 1 H2O1 g2 was studied at 600 K. Conce

Solnce55 [7]

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Let's consider the decomposition of ethanol on an alumina surface.

C₂H₅OH(g) ⇒ C₂H₄(g) + H₂O(g)

The plot of [A] vs time (t) resulted in a straight line, which indicates that the reaction follows zero-order kinetics.

The slope, 24.00 × 10²⁵ M/s, represents the rate constant, k.

<h3>What is zero-order kinetics?</h3>

It is a chemical reaction in which the rate of reaction is constant and independent of the concentration of the reacting substances

The rate law for zero-order kinetics is:

rate = 24.00 × 10²⁵ M/s

The integrated rate law for zero-order kinetics is:

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

Is the time for the amount of substance to decrease by half.

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, we can calculate the half-life [t(1/2)] using the following formula.

t(1/2) = [C₂H₅OH]₀ / 2 × k

t(1/2) = (1.25 × 10²² M) / 2 × (24.00 × 10²⁵ M/s) = 2.60 × 10⁻⁵ s

We can calculate the time required for all the 1.25 × 10²² M C₂H₅OH to decompose using the integrated rate law.

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

0 M = 1.25 × 10²² M - 24.00 × 10²⁵ M/s × t

t = 5.21 × 10⁻⁵ s

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Learn more about zero-order kinetics here: brainly.com/question/13314785

3 0

2 years ago

Plz help with this digestive system

VMariaS [17]

Answer:

(4) mechanical digestion

(5) chemical digestion

(6) enzymes

(7) pharynx

(8) peristalsis

8 0

3 years ago

Read 2 more answers

The density of a certain type of plastic is 0.81 g/cm3. If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick, w

crimeas [40]

<u>Answer:</u> The mass of plastic sheet is $8.1\times 10^4g$

<u>Explanation:</u>

The plastic sheet is in the form of cuboid. To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.0 m = 1000 cm (Conversion factor: 1 m = 100 cm)

b = breadth of cuboid = 1.0 m = 100 cm

h = height of cuboid = 1 cm

Putting values in above equation, we get:

$V=1000\times 100\times 1=10^5cm^3$

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of plastic sheet = $0.81g/cm^3$

Volume of plastic sheet = $10^5cm^3$

Putting values in equation 1, we get:

$0.81g/cm^3=\frac{\text{Mass of plastic sheet}}{10^5cm^3}\\\\\text{Mass of plastic sheet}=8.1\times 10^4g$

Hence, the mass of plastic sheet is $8.1\times 10^4g$

8 0

3 years ago

Molecules that influence protein activity by binding to sites that are distinct from the active site are called ______________ _

Rudiy27

<span>Answer: allosteric effectors</span>

6 0

3 years ago