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choli [55]
3 years ago
12

The following is a procedure that was theoretically performed by a student. Read through the procedure and answer the questions

below.1.A 10.0 mL graduated cylinder to measure 10.0 mL of a 1.00 M CaCl2 solution into an initially empty 50.0 mL beaker.2.A 50.0 mL graduated cylinder was then used to measure out 25.0 mL of 0.500 M K2CO3. This K2CO3solution was then added to the beaker containing the CaCl2 solution. The solution became cloudy, and the student concluded that a precipitate must have formed. Write a balanced chemical reaction below, including phases, and identify the chemical formula of the precipitate:
Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

Explanation:

We have the reactants as calcium chloride and potassium carbonate. Recall that we are expecting that the reaction will yield a precipitate. We must keep that in mind as we seek to write its balanced chemical reaction equation.

So we now have;

CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

Recall that the rule of balancing chemical reaction equation states that the number of atoms of each element on the right side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation.

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Which of the following scientists made an important contribution to quantum mechanics: (i) Bohr (ii) deBroglie (iii) Heisenberg
grandymaker [24]

Answer:

(i) Bohr; (ii) de Broglie; (iii) Heisenberg (v) Schrödinger

Explanation:

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4 0
3 years ago
128g of sulphur are burned in excess oxygen. What mass of sulphur dioxide forms? S + O2 --&gt; SO2 *
Rasek [7]

Mass of Sulphur dioxide : 256 g

<h3>Further explanation</h3>

Given

Reaction

S + O2 --> SO2 *

Required

Mass of Sulphur dioxide

Solution

mol of Sulphur (Ar=32 g/mol) :

mol = mass : Ar

mol = 128 : 32

mol = 4

From the equation, mol ratio S : SO2 = 1 : 1, so mol SO2 = 4

Mass of SO2 :

mass = mol x MW SO2

mass = 4 x 64

mass = 256 g

5 0
3 years ago
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