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choli [55]
3 years ago
12

The following is a procedure that was theoretically performed by a student. Read through the procedure and answer the questions

below.1.A 10.0 mL graduated cylinder to measure 10.0 mL of a 1.00 M CaCl2 solution into an initially empty 50.0 mL beaker.2.A 50.0 mL graduated cylinder was then used to measure out 25.0 mL of 0.500 M K2CO3. This K2CO3solution was then added to the beaker containing the CaCl2 solution. The solution became cloudy, and the student concluded that a precipitate must have formed. Write a balanced chemical reaction below, including phases, and identify the chemical formula of the precipitate:
Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

Explanation:

We have the reactants as calcium chloride and potassium carbonate. Recall that we are expecting that the reaction will yield a precipitate. We must keep that in mind as we seek to write its balanced chemical reaction equation.

So we now have;

CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)

Recall that the rule of balancing chemical reaction equation states that the number of atoms of each element on the right side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation.

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3 years ago
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What volume in milliliters of concentrated HCl (12 M) is needed to make 1500 mL of a 3.5 M solution?
Leviafan [203]
This process involves the dilution of the 12 molar HCl. To reduce the concentration, we need to set up an equality so that we know how much of the 12M we need to make the 3.5M.

12 moles HCl 3.5 moles HCl
——————— = ———————
1 Liter of Soln ‘x’ Liters of Soln

Notice that the 12 moles over the 1 liter is equal to 12 molar; in doing this, we’re maintaining the concentration of the initial HCl. By setting it equal to the 3.5 over ‘x’, we’re still maintaining the concentration.

After solving, we find that ‘x’ equals 0.292. This value means that in 0.292 liters of our 12 M HCl solution, there are 3.5 moles of HCl. But, we’re not done yet.

0.292 liters of 12 M HCl can make 1 liter of 3.5 M HCl, but the question asks for 1.5 liters. To get this, multiply 0.292 liters by 1.5, and the new result, 0.4375, represents the amount of 12 M HCl required to prepare a 1500 mL 3.5 M HCl solution.
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4 years ago
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