Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is
(b) The normal boiling point of water (J·K−1·mol−1) is
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
= =
→ phases
ΔH → enthalpy of transition
T → temperature transition
=
= ( is the enthalpy of fusion of water)
=
(b)
= ( is the enthalpy of vaporization)
=
(c) =
°° = °°ΔT
°°
= 109J/mole
Answer:
Zn+H2O ------ ZnO + H2 is the correct answer
Answer:
B
CuO
H2
Explanation:
hydrogen will oxidized to form water