When you write the equation of a circle in the form
![(x-x_0)^2+(y-y_0)^2=r^2](https://tex.z-dn.net/?f=%28x-x_0%29%5E2%2B%28y-y_0%29%5E2%3Dr%5E2)
Then the center of the circle has coordinates
and the radius is ![r](https://tex.z-dn.net/?f=r)
So, in your case, the center of the circle is ![(3,7)](https://tex.z-dn.net/?f=%283%2C7%29)
Answer:
the correct option is D.)
![x = \frac{3}{2} \: and \: y = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20%20%5C%3A%20and%20%5C%3A%20y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Step-by-step explanation:
here is the solution :-
=》y = -x + 2
=》y = 3x - 4
so, by equating both equations we get,
=》-x + 2 = 3x - 4
=》2 + 4 = 3x + x
=》6 = 4x
=》x = 6 / 4
![x = \frac{3}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20)
plugging the value of x in equation 2,
=》
![y = - \frac{ 3}{2} + 2](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B%203%7D%7B2%7D%20%20%2B%202)
=》
![y = \frac{ - 3 + 4}{2}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%20-%203%20%2B%204%7D%7B2%7D%20)
=》
![y = \frac{1}{2}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Answer:
study of the geometric properties of solutions to polynomial equations, including solutions in dimensions beyond three. (Solutions in two and three dimensions are first covered in plane and solid analytic geometry, respectively.)
Step-by-step explanation:
A) Q + N = 63
B) .25Q + .05N = 8.35
Multiplying Equation B by -4
B) -Q -.2N = -33.40 then adding it to A)
A) Q + N = 63
.8 N = 29.60
N = 37
Q = 63 - 37 = 26