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galben [10]
3 years ago
12

Underneath the ocean floor, methane can exist as a solid known as methane hydrate. Methane hydrate forms when large amounts of m

ethane become trapped in the crystal structure of water, which develops into a solid similar to ice. A scientist working for a deep water drilling company is studying the properties of the three different phases of methane: methane hydrate, liquified natural gas, and natural gas. Which of the properties is true
Chemistry
1 answer:
mezya [45]3 years ago
8 0

Answer:

Methane is present in solid, liquid and gaseous form.

Explanation:

Methane hydrate is present in solid state when the hydrogen-bonded water and methane gas come into contact at high pressures and low temperatures in the deep oceans while on the other hand, methane which is present inside the earth surface in gaseous form due to non-availability of water that can combine with methane. Methane is also found in liquid form when it is cool with high pressure and low temperature.

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What happens when a solid is dissolved into a liquid?
daser333 [38]

When a solid dissolves in a liquid to form a solution, solid particles become evenly dispersed among liquid particles.

<h3>What are solutions?</h3>

Solutions are formed when a solute particle dissolves in another substance known as a solvent.

Usually, solutions are formed when solids dissolve in liquids.

The solid is the solute while the liquid is the solvent.

When a solid dissolves in a liquid, solid particles become evenly dispersed among liquid particles.

Therefore, solutions are formed when solute particles dissolve in solvents.

Learn more about solutes and solutions at: brainly.com/question/25326161

#SPJ1

6 0
2 years ago
Read 2 more answers
The decomposition reaction of carbon disulfide to carbon monosulfide and sulfur is first order with k = 2.80 ✕ ✕ 10−7 sec-1 at 1
madam [21]

Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

              b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

                          CS_2(g)\rightarrow CS(g)+S(g)

at t=0                    4.83g             0          0

at t=37 days        4.83 - x            x           x

here,

x = amount of CS_2 utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

k=\frac{2.303}{t}log\frac{A_o}{A}

where, k = rate constant

t = time

A_o = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

k=2.80\times10^{-7}sec^{-1}

t = 370 days = 3196800 sec

A_o = 4.83

A = 4.83-x

Putting values in the above equation, we get

2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)

x = 2.85g

Amount of CS_2 remained after 37 days = 4.83 - x

                                                                     = 1.97g

b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

6 0
3 years ago
Makes up the core of the other planets<br> stars with an M and ends with E
Sonbull [250]

Answer:

its iron not m or e

Explanation:

3 0
2 years ago
Read 2 more answers
The picture below is a great example of __________ biodiversity.
ss7ja [257]
Low because it is not diverse. It is just seed corn.
6 0
3 years ago
You are given two aqueous solutions with different ionic solutes (Solution A and Solution B). What if you are told that Solution
klio [65]

Answer:

Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.  

It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,  

% by mass = mass of solute/mass of solution * 100

Now the formula for molality is,  

Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams

Now molality of solution A is,  

m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)

m = 2.07

Now the molality of solution B is,  

m = 15/58.5 * 1000/85

m = 3.02

Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).

5 0
3 years ago
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