Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
Red ink since the substance is has a lower viscosity
Answer:
I would go with the first option. It shows how people having been releasing more and more carbon dioxide into the atmosphere.
Explanation:
I think it’s solar but I’m sorry if that’s wrong :)
The products : Zn₃(PO₄)₂ (s) + KClO₃ (aq)
<h3>Further explanation</h3>
Given
reaction: Zn(ClO₃)₂ (aq) + K₃PO₄ (aq)
Required
The products
Solution
Double-Replacement reactions : an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
General formula :
AB + CD ⇒ AD + CB
One of the characteristics of the double replacement reaction is the presence of precipitated compounds
Zn(ClO₃)₂ (aq) + K₃PO₄ (aq) ⇒ Zn₃(PO₄)₂ (s) + KClO₃ (aq)
Zn₃(PO₄)₂ (s)⇒ precipitated compounds, so that this reaction can occur
