Answer:
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Explanation:
How many particles would be found in a 1.224 g sample of K2O
2 answers:
Answer:
7.8286×10²¹ particles.
Explanation:
First we need to calculate the total molar mass of the compound, in this case:
Potassium (K) = 39.1 g/mol × 2 = 78.2 +
Oxigen (O) = 16 g/mol × 1 = <u> 16 </u>
Total(K₂O) = 94.2 g/mol
Then, we calculate the number of moles of the compound in the sample, this is done dividing de mass of the sample by the molar mass:
mol = 0.013 moles in our sample.
Finally, we calculate the total number of particles. The costant known as Avogadro number (6.022×10²³) is the number of particles or atoms contained in a mole of any substance. We need to multiply the number of moles by the Avogadro number.
particles = 0.013 mol × (6.022×10²³ particles/mol) = 7.8286×10²¹ particles.
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Answer: -
1 mol
Explanation: -
Number of moles of Sulphur S = 7
Number of moles of O2 = 9
The balanced chemical equation for the reaction is
2S (s)+3 O2 (g)→2SO3(g)
From the above reaction we can see that
3 mol of O2 react with 2 mol of S
9 mol of O2 will react with
= 6 mol of S
Unreacted S = 7 - = 1 mol.
If a reaction vessel initially contains 7 mol S and 9 mol O2
1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible