Answer:
7.8286×10²¹ particles.
Explanation:
First we need to calculate the total molar mass of the compound, in this case:
Potassium (K) = 39.1 g/mol × 2 = 78.2 +
Oxigen (O) = 16 g/mol × 1 = <u> 16 </u>
Total(K₂O) = 94.2 g/mol
Then, we calculate the number of moles of the compound in the sample, this is done dividing de mass of the sample by the molar mass:
mol = 0.013 moles in our sample.
Finally, we calculate the total number of particles. The costant known as Avogadro number (6.022×10²³) is the number of particles or atoms contained in a mole of any substance. We need to multiply the number of moles by the Avogadro number.
particles = 0.013 mol × (6.022×10²³ particles/mol) = 7.8286×10²¹ particles.
The given formula contains two carbon along with six hydrogen and an oxygen.
The possible isomers from are ethanol and dimethyl ether.
Ehtanol is an alcohol containing a hydroxyl group whereas dimethyl ether is an ether containing an oxygen between two methyl
The structure of two isomers are:
Answer: The volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L
At constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts, then
PV = c
Thus, if the pressure increases, the volume decreases, and if the pressure decreases, the volume increases.
It is not necessary to know the exact value of the constant c to be able to use this law since for a fixed amount of gas at constant temperature, it is satisfied that,
P₁V₁ = P₂V₂
Where P₁ and P₂ as well as V₁ and V₂ correspond to pressures and volumes for two different states of the gas in question.
In this case the first oxygen gas state corresponds to P₁ = 1.00 atm and V₁ = 3.60 L while the second state would be P₂ = 2.50 atm and V₂ = y. Substituting in the previous equation,
1.00 atm x 3.60 L = 2.50 atm x y
We cleared y to find V₂,
V₂ = y = = 1.44 L
Then, <u>the volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L</u>