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user100 [1]
3 years ago
11

How many particles would be found in a 1.224 g sample of K2O

Chemistry
2 answers:
irina [24]3 years ago
6 0

Answer:

7.8286×10²¹ particles.

Explanation:

First we need to calculate the total molar mass of the compound, in this case:

Potassium (K) = 39.1 g/mol × 2 =  78.2 +

Oxigen (O)     =     16 g/mol × 1  = <u>    16   </u>

                                Total(K₂O) = 94.2 g/mol

Then, we calculate the number of moles of the compound in the sample, this is done dividing de mass of the sample by the molar mass:

mol =\frac{1.224 g}{94.2 g/mol}

mol = 0.013 moles in our sample.

Finally, we calculate the total number of particles. The costant known as Avogadro number (6.022×10²³) is the number of particles or atoms contained in a mole of any substance. We need to multiply the number of moles by the Avogadro number.

particles = 0.013 mol × (6.022×10²³  particles/mol) = 7.8286×10²¹ particles.

lbvjy [14]3 years ago
4 0

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

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muminat

Answer:

nickel

It also tells you the number of electrons that the element has in its outside shells. If the atomic number of nickel is 28 then every atom of nickel has 28 protons in its nucleus and 28 electrons outside the nucleus.

Explanation:

5 0
3 years ago
a 360mg sample of sugar (molar mass of 180 g/mol) is dissolved in enough water to produce 200mL of solution. after the sugar is
Pie
360 mg / 1000    => 0.36 g

molar mass => 180 /mol

number of moles:

mass of solute / molar mass

0.36 / 180 => 0.002 moles

Volume solution = 200 mL / 1000 => 0.2 L

M = n / V

M = 0.002 / 0.2

M = 0.01 mol/L

hope this helps!
5 0
3 years ago
What mass of f2 is needed to produce 120. g of pf3 if the reaction has a 78.1% yield?
lesya692 [45]

write the equation for the reaction

that is 6 F2 +P4 =4 PF3

find the theoretical mass that is

let the theoretical yield be represented by y

theoretical yield = 78.1/100 = 120/y

y= 153.6 grams

find the number of moles of  PF3

moles = mass/molar mass

= 153.6/87.97 =1.746 moles

by use of mole ratio between  F2 :PF3 which is 6:4 the moles of F2 is therefore= 1.746 x 6/4 = 2.62 moles

mass = moles x molar mass

= 1.746 moles x38 g/mol = 99.6 grams

6 0
3 years ago
Indica las condiciones que debe cumplir una colisión entre moléculas para que se produzca una reacción química
g100num [7]

Answer:

Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.

6 0
3 years ago
Show work please! :)
SIZIF [17.4K]
What’s the question!??
6 0
2 years ago
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