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3 years ago

14

Where is most of the water on earth found? What percentage?

1 answer:

bezimeni [28]3 years ago

8 0

Answer:

The ocean holds about 97 percent of the Earth's water; the remaining three percent is found in glaciers and ice, below the ground, in rivers and lakes. Of the world's total water supply of about 332 million cubic miles of water, about 97 percent is found in the ocean.

wait..if you asking about the country it's Brazil✌️

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Is the equivilant of 39.3 inches

Stels [109]

Answer:

3 mm is equal to 1.547244 inches. To do the calculation, use our online calculator. In the box next to “millimeters”, type 39.3. Once you have entered the number, the calculator displays the results. Once you have taken note of the numbers, click the reset button if you want to make other conversions.

3 0

3 years ago

If 54 g of Al reacted with 160 g of O2, find out the weight of product

Oxana [17]

Answer:

number of Al atom =54÷27=2atom of Al. number of o atom = 160÷16=10 atom of o . =214U MASS of ALO2.

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3 years ago

Calculate the ionic strength of a solution of iron (iii) carbonate, fe2(co3)3 of concentration 0.020 mol dm

Ede4ka [16]

E=b(x^3)×co3x{fe2}+13^3

6 0

3 years ago

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the

alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.4 atm

$P_2$ = final pressure of gas = 1.0 atm

$V_1$ = initial volume of gas = 250 mL

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $15^oC=273+15=288K$

$T_2$ = final temperature of gas = $27^oC=273+27=300K$

Now put all the given values in the above equation, we get:

$\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}$

$V_2=625mL$

Therefore, the volume of the bubble is, 625 mL

7 0

3 years ago

A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific h

nata0808 [166]

Answer:

Specific heat of alloy = 0.2 j/ g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of bold = 25 g

Heat absorbed = 250 J

Initial Temperature = 25°C

Final temperature = 78°C

Specific heat of alloy = ?

Solution:

Change in temperature:

ΔT = 78°C - 25°C

ΔT = 53°C

Now we will put the values in formula.

Q = m.c. ΔT

250 j = 25 g × c ×53°C

250 j = 1325 g.°C × c

250 j / 1325 g.°C = c

c = 0.2 j/ g.°C

8 0

3 years ago