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tankabanditka [31]
3 years ago
15

Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two sys

tems reach equilibrium. Then both springs are compressed and released. Which one oscillates faster?
a) The spring with the heavier ball,
b) Springs oscillate with the same frequency,
c) The spring with the light ball.
Physics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

b) Springs oscillate with the same frequency,

Explanation:

expression for frequency of vibration of mass hanging from a spring is given as follows

f = \frac{1}{2\pi} \times \sqrt{\frac{k}{m} }

k is force constant of spring and m is mass vibrating .

In the present case, if mass stretches the spring by x and remains balanced

mg = k x

\frac{k}{m} =\frac{g}{x}

g and x are same  for both cases

\frac{k}{m} will also be same for both cases .

Hence frequency of vibration will also be same for both the balls .

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Answer:

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Explanation:

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Find the coordinates of the center of mass of the triangle.

Solution:-

- The center of mass of any triangle is at the intersection of its medians.

- So let’s say we have a triangle with vertices at points (0,0) , (a,0) , and (0,b).

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                                       bx−ay=0

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                                     2bx+ay=ab

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                                     ay + 2ay = ab , 3ay = ab , y = b/3

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  • So the distance from the median to each leg of the triangle is 1/3 length of other leg.

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