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3 years ago

Which electromagnetic wave enables us to see objects?

Physics

2 answers:

disa [49]3 years ago

4 0

Visible light
Choose B

ASHA 777 [7]3 years ago

3 0

Answer: The correct answer is "visible rays".

Explanation:

Electromagnetic wave: In electromagnetic wave, both the electric fields and the magnetic field are directed in the direction of the propagation of the electromagnetic wave. Electromagnetic wave travels in vacuum.

It travels with the speed of the light.

For example, X-rays, gamma rays, infrared rays and visible region.

The electromagnetic spectrum consists of visible region and an invisible region.

Visible region of the electromagnetic can be seen by naked eyes. Its range is 400 nm to 700 nm.

We are unable to see infrared rays, ultraviolet light and gamma rays.

Therefore, the correct option is (b).

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An object is dropped from a height H. During the final second of its fall, it traverses a distance of 53.2 m. What was H? An obj

Serhud [2]

Answer:

H = 171.90 m

Explanation:

given data

distance = 53.2 m

height = H

to find out

height H

solution

we know height is here H = $\frac{1}{2} gt^2$ ......................1

here t is time and a is acceleration

we find t first

we know during time (t -1) s , it fall distance (H - 53.2) m

so equation of distance

$H - 53.2 = \frac{1}{2} g (t-1)^2$

$H - 53.2 = \frac{1}{2} g (t^2-2t+1)$

$H - 53.2 = \frac{1}{2} gt^2-gt+\frac{1}{2} g$ ................2

now subtract equation 2 from equation 1 so we get

$H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)$

53.2 = gt - $\frac{1}{2} g$

53.2 = 9.81 t - $\frac{1}{2} 9.8$

t = 5.92 s

so from equation 1

H = $\frac{1}{2} (9.81)5.92^2$

H = 171.90 m

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AURORKA [14]

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What is the momentum of a 2.0kg ball rolling at 6.0 m/s

irga5000 [103]

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