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3 years ago

Which electromagnetic wave enables us to see objects?

Physics

2 answers:

disa [49]3 years ago

4 0

Visible light
Choose B

ASHA 777 [7]3 years ago

3 0

Answer: The correct answer is "visible rays".

Explanation:

Electromagnetic wave: In electromagnetic wave, both the electric fields and the magnetic field are directed in the direction of the propagation of the electromagnetic wave. Electromagnetic wave travels in vacuum.

It travels with the speed of the light.

For example, X-rays, gamma rays, infrared rays and visible region.

The electromagnetic spectrum consists of visible region and an invisible region.

Visible region of the electromagnetic can be seen by naked eyes. Its range is 400 nm to 700 nm.

We are unable to see infrared rays, ultraviolet light and gamma rays.

Therefore, the correct option is (b).

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Please help Need good grade

ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the range

Using formula of range

$R=\dfrac{v^2\sin(2\theta)}{g}$ ...(I)

The range for the other angle is

$R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$ ....(II)

Here, distance and speed are same

On comparing both range

$\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$

$\sin(2\theta)=\sin(2\times(\alpha-\theta))$

$\sin120=\sin2(\alpha-60)$

$120=2\alpha-120$

$\alpha=\dfrac{120+120}{2}$

$\alpha=120^{\circ}$

Hence, The other angle is 120°

6 0

3 years ago

tom and ted are sitting on seprate chairs that have wheels. tom pushes ted and, in turn, he starts moving too. in which directio

IceJOKER [234]

In the direction opposite to his push.

5 0

3 years ago

Please help!

Yanka [14]

Answer:

V=3.57 × 10^6 m/s

hope it is helpful..

7 0

2 years ago

A traditional unit of length in Japan is the ken (1ken =1.97 m) . What are the ratios of (a) square kens to a square meters? and

Law Incorporation [45]

4 . I hope I helped your welcome

6 0

3 years ago

A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway

Andru [333]

Answer:

63.44 rad/s

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet $v_{1}$ = 250 m/s

final velocity of bullet $v_{2}$ = 140 m/s

loss of kinetic energy of the bullet = $\frac{1}{2}m(v^{2} _{1} - v^{2} _{2})$

==> $\frac{1}{2}*0.0033*(250^{2} - 140^{2} )$ = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = $\frac{1}{2} mv^{2}$

70.785 = $\frac{1}{2}*0.25*v^{2}$

566.28 = $v^{2}$

$v= \sqrt{566.28}$ = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 = 63.44 rad/s

5 0

2 years ago