<span>analyze. Analyze means to study or examine
something carefully in a methodical way. ... This verb analyze comes
from the noun analysis. The noun analysis was in turn borrowed from
Greek, from analyein, or "to dissolve."
hope it helps;)
</span>
¡Hellow!
For this problem, first, lets convert the seconds in hours:
5,4x10³
5400
h = sec / 3600
h = 5400 s / 3600
h = 1,5
Let's recabe information:
d (Distance) = 386 km
t (Time) = 1,5 h
v (Velocity) = ?
For calculate velocity, let's applicate formula:
![\boxed{\boxed{\textbf{d = v * t} } }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctextbf%7Bd%20%3D%20v%20%2A%20t%7D%20%7D%20%7D)
Reeplace according we information:
386 km = v * 1,5 h
v = 386 km / 1,5 h
v = 257,33 km/h
The velocity of the train is of <u>257,33 kilometers for hour.</u>
<u></u>
Extra:
For convert km/h to m/s, we divide the velocity of km/h for 3,6:
m/s = km/h / 3,6
Let's reeplace:
m/s = 257,33 km/h / 3,6
m/s = 71,48
¿Good Luck?
Answer:
200 feet
Explanation:
According to my research on the studies conducted by motor vehicles safety professionals, It is said that based on the information provided within the question the driver needs a mirror in which he/she is able to view the roadway 200 feet to the rear of the vehicle. This is a safety precaution which allows the driver a broader environmental awareness leading to less accidents.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer: q = -52.5 μC
Explanation:
The complete question is given thus;
A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).
SOLVING:
from the given parameters we can solve this problem.
Given that the
Speed = 280 m/s
y = 70mm
B = -30 * 10⁻⁶T
Using the equation for magnetic field we have;
Β = μqv*r / 4πr²
making q (charge) the subject of formula we have that;
q = B * 4 *πr² / μqv*r
substituting the values gives us
q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]
q = -52.5 μC
cheers i hope this helped !!!
To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be
![H = Ae\sigma T^4](https://tex.z-dn.net/?f=H%20%3D%20Ae%5Csigma%20T%5E4)
Where
A = Surface area
e = Emissivity that characterizes the emitting properties of the surface
= Universal constant called the Stefan-Boltzmann constant ![(5.67*10^{-8}m^{-2}K^{-4})](https://tex.z-dn.net/?f=%285.67%2A10%5E%7B-8%7Dm%5E%7B-2%7DK%5E%7B-4%7D%29)
T = Absolute temperature
The total heat loss would be then
![Q = H_2 -H_1](https://tex.z-dn.net/?f=Q%20%3D%20H_2%20-H_1)
![Q =Ae\sigma T_2^4-Ae\sigma T_1^4](https://tex.z-dn.net/?f=Q%20%3DAe%5Csigma%20T_2%5E4-Ae%5Csigma%20T_1%5E4)
![Q = Ae\sigma (T_2^4-T_1^4)](https://tex.z-dn.net/?f=Q%20%3D%20Ae%5Csigma%20%28T_2%5E4-T_1%5E4%29)
![Q = (1.2)(1)(5.67*10^{-8})(303^4-280^4)](https://tex.z-dn.net/?f=Q%20%3D%20%281.2%29%281%29%285.67%2A10%5E%7B-8%7D%29%28303%5E4-280%5E4%29)
![Q = 155.29J](https://tex.z-dn.net/?f=Q%20%3D%20155.29J)
Therefore the net rate of heat loss from the body by radiation is 155.29J