The question for this problem would be the minimum headphone delay, in ms, that will cancel this noise.
The 200 Hz. period = (1/200) = 0.005 sec. It will need to be delayed by 1/2, so 0.005/2, that is = 0.0025 sec. So converting sec to ms, will give us the delay of:Delay = 2.5 ms.
Answer:
Option A
Explanation:
From fundamental equation of motion
where v is the final velocity, u is the initial velocity, a is the acceleration of the body and s is the displacement.
Since the initial velocity is zero
Making acceleration, a the subject of the formula then
Substituting 5 m/s for v and 2.5 m for s then
Answer:
Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.
Explanation:
Explanation:
Given that,
Radius in which the satellite orbits, r = 6588 km
Solution,
The centripetal force acting on the satellite is balanced by the gravitational force acting between earth and the satellite. Its expression can be written by :
, M is the mass of earth
v = 7782.53 m/s
Let t is the time required to complete one orbit. It can be calculated as :
t = 5318.78 seconds
or
t = 1.47 hour
Therefore, this is the required solution.
Answer: 2.5 seconds
Explanation:
We know that the acceleration is:
a(t) = 1.7 m/s^2
To get the velocity function, we must integrate over time, and we will get:
v(t) = (1.7m/s^2)*t + v0
Where v0 is the initial velocity, in this case, we assume that we start at 23.6m/s, then the initial velocity is:
v0 = 23.6 m/s
Then the velocity equation is:
v(t) = (1.7m/s^2)*t + 23.6 m/s
Now we want to find the value of t such v(t) = 27.8 m/s
Then:
v(t) = 27.8 m/s = (1.7m/s^2)*t + 23.6 m/s
27.8 m/s - 23.6 m/s = (1.7m/s^2)*t
4.2 m/s = (1.7m/s^2)*t
4.2m/s/(1.7m/s^2) = t = 2.5 s
Then at that acceleration, you need 2.5 seconds.