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Kryger [21]
3 years ago
5

name the metal which form the filament of an electric bulb. what is the function of contact wire in bulb.​

Physics
2 answers:
harina [27]3 years ago
5 0
Incandescent light bulbs consist of an air-tight glass enclosure (the envelope, or bulb) with a filament of tungsten wire inside the bulb, through which an electric current is passed. Contact wires and a base with two (or more) conductors provide electrical connections to the filament.
g100num [7]3 years ago
4 0

Answer:

tungsten wire

Incandescent light bulbs consist of an air-tight glass enclosure (the envelope, or bulb) with a filament of tungsten wire inside the bulb, through which an electric current is passed. Contact wires and a base with two (or more) conductors provide electrical connections to the filament.

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If 1.0 joule of work is required to move a charge of 1.0 coulomb between two points is an electric field the potential differenc
deff fn [24]

Answer:1V

Explanation: simply put it

V=W/q

=1/1

=1V

6 0
3 years ago
In a Young's double-slit experiment, a set of parallel slits with a separation of 0.142 mm is illuminated by light having a wave
Alexandra [31]

Answer:

1.152\ \mu m

1.44\ \mu m

Explanation:

d = Gap between slits = 0.142 mm

\lambda = Wavelength of light = 576 nm

L = Distance between light and screen = 3.5 m

m = Order = 2

Difference in path length is given by

\delta=dsin\theta=m\lambda\\\Rightarrow \delta=2\times 576\times 10^{-9}\\\Rightarrow \delta=0.000001152\ m\\\Rightarrow \delta=1.152\times 10^{-6}\ m=1.152\ \mu m

The difference in path lengths is 1.152\ \mu m

For dark fringe the difference in path length is given by

\delta=(m+\dfrac{1}{2})\lambda\\\Rightarrow \delta=(2+\dfrac{1}{2})\times 576\times 10^{-9}\\\Rightarrow \delta=0.00000144\ m=1.44\ \mu m

The difference in path length is 1.44\ \mu m

5 0
3 years ago
A 2.50 gram rectangular object has measurements of 22.0 mm, 13.5 mm, and 12.5 mm. what is the object's density in units of g/ml?
Zinaida [17]
G/mL is equivalent to g/cm^3, so we first convert the dimensions into cm:
2.20 cm, 1.35 cm, and 1.25 cm
Then the total volume is: V = lwh = 3.7125 cm^3
To get the density, we divide mass by volume: 2.50 g / 3.7125 cm^3 = 0.6734 g/cm^3 = 0.6734 g/mL
4 0
4 years ago
explain which properties of metals make sterling silver the best material for you to create hammered earrings.
7nadin3 [17]

It is malleable

Explanation:

The property that makes metals such as sterling silver the best to create hammered earrings is their malleability.

All metals have a unique and fascinating property of being malleable. They can be carved into any of shape. When hammered they simply draw out and retain their long range ordering of their crystal lattice.

This is made possible by the presence of metallic bonding between the atoms.

  • The bulk of the physical properties of metals can be attributed the metallic bonds in them.
  • Metals have large sea of electrons in them.
  • In forming metallic bonds, there is an attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by loosing their outermost shell electrons.
  • Metals like silver have low ionization energy.
  • When they are hammered, they spread out the energy from the hammering.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

8 0
3 years ago
Potential energy results from the ______or position of an object.
Burka [1]

Answer:

Mass

Explanation:

8 0
3 years ago
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