Answer: The chemical formula for the compound of these two elements is 
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here metal lead is having an oxidation state of +4 called as 
cation and sulphur non metal has oxidation state of -2 called as 
. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral
The chemical formula for the compound of these two elements is
Initial velocity (u) = 0 m/s
Final velocity (v) = 25 m/s
time taken (t) = 10s
acceleration (a) = ?
Now,
Acceleration is rate of change of velocity, so formula is
a = (v - u)/t
a = (25 - 10)/10
a = 15/10
a = 1.5 m/(s^2)
Use this value of a.
Answer:
The slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
Explanation:
Given;
The slope, dy/dx = 2x(y-6) - 4
2x(y-6) - 4 = 2xy - 12x - 4, divide through by 'x'
dy/dx = 2y -12 - 4/x
The slopes of the linear elements on the lines, x =0, y = 5, y = 6, y = 7.
At x = 0, and y = 5
dy/dx = 2y -12 - 4/x
dy/dx = 2(5) - 12 = -2
At x = 0, and y = 6
dy/dx = 2y -12 - 4/x
dy/dx = 2(6) - 12 = 0
At x = 0, and y = 7
= 2y -12 - 4/x
dy/dx = 2(7) - 12 = 2
Therefore, the slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
Answer:
x = 95 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
Now we can find the acceleration
19 = 0 *a*(10)
a = 1.9 [m/s]
With the second equation we can find the distance:
where:
x = distance [m]
(19)² = (0)² + (2*1.9*x)
3.8*x = 361
x = 95 [m]
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