A long solenoid (radius = 3.0 cm, 2500 turns per meter) carries a current given by I = 0.30 sin(200 t) A, where t is measured in
s. When t = 2.5 ms, what is the magnitude of the induced electric field at a point which is 4.0 cm from the axis of the solenoid? The answer is 1.9*10^-3 V/m. please explain in detail
1 answer:
Answer:
1.86 × 10 ∧-3 V/m
≅ 1.9 × 10 ∧-3 V/m
Explanation:
Radius of long solenoid (R)= 3 cm
Turns per meter (n) = 2500
current flowing in coil (I) = 0.30 sin (200 t)
Time (t) = 2.5 ms
Distance at which electric field calculated (r) = 4 cm
The main solution is shown in the picture attached below.
Thank you and i hope it helps.
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