Question

A long solenoid (radius = 3.0 cm, 2500 turns per meter) carries a current given by I = 0.30 sin(200 t) A, where t is measured in s. When t = 2.5 ms, what is the magnitude of the induced electric field at a point which is 4.0 cm from the axis of the solenoid? The answer is 1.9*10^-3 V/m. please explain in detail

Answer 1

Answer:

1.86 × 10 ∧-3 V/m

≅ 1.9 × 10 ∧-3 V/m

Explanation:

Radius of long solenoid (R)= 3 cm

Turns per meter (n) = 2500

current flowing in coil (I) = 0.30 sin (200 t)

Time (t) = 2.5 ms

Distance at which electric field calculated (r) = 4 cm

The main solution is shown in the picture attached below.

Thank you and i hope it helps.