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Savatey [412]
3 years ago
15

a few drops of perfume were spilt on the floor a few minutes later ghe perfume could be smelt a few meters away what 2 processes

had taken​
Chemistry
1 answer:
MArishka [77]3 years ago
6 0

Answer:

evaporation and diffusion

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A recipe for chocolate cake calls for 236.6 mL of buttermilk.
Mice21 [21]

Answer:236.6

Explanation:

5 0
3 years ago
This diagram shows the forces acting on a car. The center dot represents the car, and the arrows represent the forces acting on
Mariulka [41]

Answer : The correct option is B- Towards the left.

Solution : Given,

Force on car in upward direction, F_1 = 6000 N

Force on car in downward direction, F_2 = 6000 N

Force on car in right direction, F_3 = 5000 N

Force on car in left direction, F_4 = 6000 N

Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.

Formula :  F =  m × a

where, F is force, m is mass and a is acceleration.

From the given diagram we conclude that the F_1 and F_2 are in opposite direction and the force acting on car are same. So, their net force is zero.

And in case of F_3 and F_4, the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because F_4 is higher than the F_3.

So, the car will accelerate towards left direction.


3 0
3 years ago
What quantity of energy would be necessary to boil water with a mass of
anygoal [31]

Answer:

i think 554 I think

Explanation:

maybe ..

6 0
3 years ago
If a car jack's output force is 1000 N and the mechanical advantage is 6.8, what is the input force?
Travka [436]
Answer
147.06N
Explanation:
MA=Load/Effort
6.8=1000/x
Finding x you make x the subject and divide 1000 by 6.8 which is 147.06N
4 0
2 years ago
A 13.00 g sample of citric acid reacts with an excess of baking soda What is the theoretical yield of carbon dioxide
viva [34]

Answer:

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the <em>moles of H₃Cit </em>

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the <em>moles of CO₂ </em>

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the <em>mass of CO₂ </em>

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

4 0
3 years ago
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