<u>Answer:</u>
The freezing point of a 1.7 mole aqueous ethylene glycol solution is 3.2°C
<u>Explanation:</u>
Moles present in aqueous ethylene glycol solution= m=1.7
Depression constant for water = 
= 1.8 deg C/m
According to formula
=1.8* 1.7
=3.2
Hence the freezing point of aqueous ethylene glycol solution is 3.2°C
It lowers the activation energy.
Answer:
The volume of the gas is 0.015 m^3.
Explanation:
mass, m = 32 g
Temperature, T = 45 °C = 45 + 273 = 318 K
Pressure, P = 728 mm of hg = 0.728 x 13.6 x 1000 x 9.8 = 97027.84 Pa
Atomic mass = 4 x 12 + 10 x 1 = 58 g
Use the ideal gas equation
Let the volume is V.
P V = n R T
A hydrate is a substance that contains water or its constituent elements. When this substance is heated, water is evaporated leaving an unhydrate. From this sample, the amount of water present would be equal to 2.73 g. Hope this answers the question. Have a nice day.
2 C2H6 + 7 O2 ➡️ 4 CO2 + 6 H2O
