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Savatey [412]
3 years ago
15

a few drops of perfume were spilt on the floor a few minutes later ghe perfume could be smelt a few meters away what 2 processes

had taken​
Chemistry
1 answer:
MArishka [77]3 years ago
6 0

Answer:

evaporation and diffusion

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What would be the freezing point of a 1.7 mole aqueous ethylene glycol solution? The freezing point depression constant for wate
vaieri [72.5K]

<u>Answer:</u>

The freezing point of a 1.7 mole aqueous ethylene glycol solution is 3.2°C

<u>Explanation:</u>

Moles present in aqueous ethylene glycol solution= m=1.7

Depression constant for water = K_b= 1.8 deg C/m

According to formula  

T_f=K_b*m

T_f=1.8* 1.7

=3.2

Hence the freezing point of aqueous ethylene glycol solution is 3.2°C

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How does a catalyst affect the activation energy of a chemical reaction?
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Question
deff fn [24]

Answer:

The volume of the gas is 0.015 m^3.

Explanation:

mass, m = 32 g

Temperature, T = 45 °C = 45 + 273 = 318 K

Pressure, P = 728 mm of hg = 0.728 x 13.6 x 1000 x 9.8 = 97027.84 Pa

Atomic mass = 4 x 12 + 10 x 1 = 58 g

Use the ideal gas equation

Let the volume is V.

P V = n R T

97027.8 \times V = \frac{32}{58}\times 8.31 \times 318 \\\\V = 0.015 m^3  

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A hydrate is a substance that contains water or its constituent elements. When this substance is heated, water is evaporated leaving an unhydrate. From this sample, the amount of water present would be equal to 2.73 g. Hope this answers the question. Have a nice day.
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Balance the following equation by providing the correct coefficients C2H6 + O2 -&gt; CO2 + H2O
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