What amount of energy is required to change a spherical drop of water with a diameter of 1.80 mm to three smaller spherical drop
1 answer:
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The question displayed below shows the missing information which therefore completes the question.
An organic compound contains C, H, N and O. Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2587 g of CO2 and 0.0861 g of H2O. A sample of 0.4831 g of the compound was analyzed for nitrogen by the Dumas method. The compound is first reacted by passage over hot: The product gas is then passed through a concentrated solution of to remove the. After passage through the solution, the gas contains and is saturated with water vapor. At STP, 38.9 mL of dry N2 was obtained. In a third experiment, the density of the compound as a gas was found to be 2.86 g/L at 127°C and 256 torr. What are the empirical and molecular formulas of the compound? (Enter the elements in the order: C, H, N, O.)
Answer:
the empirical formula =
the molecular formula =
Explanation:
From the given information:
= 0.0706g of C
0.0097g of H
Given that N2 at STP = 1 atm, 273 K and V = 0.0389 L
PV = nRT
n = PV/RT
n = 0.00173 mol of N2
The oxygen in the sample = The total grams in sample - gram in H - gram in C
The oxygen in the sample = 0.1023 g - 0.0097 g - 0.706 g
The oxygen in the sample = 0.022 g of O
The number of moles of
= 0.001375 mol of O
O in product = 0.02136 mol of O
∴
we are meant to divide the moles of each compound by the smallest number of moles; we have:
Thus; the empirical formula =
To estimate the molecular formula; we have:
MM = 272.86 g/mol
Also; the molar mass of = 248 g/mol
∴
Thus; we can conclude that empirical formula as well as the molecular formula are the same.
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Decreasing the temperature of the reaction,the reaction shifts forward.
The explanation is given below.
Explanation:
If the temperature of the reaction mixture is increased,then the equilibrium will shift to decrease the temperature.
If the temperature of the reaction mixture is decreased,then the equilibrium will shift to increase the temperature.
During the formation of the ammonia,it gives off heat.So it is an exothermic reaction.
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A decrease in the temperature favors the reaction that is exothermic (the forward reaction)because it produces energy.Therefore,if the temperature is decreased,the yield of the ammonia increases.
<em>Therefore if the temperature is increased,the reaction shifts forward and the yield of the ammonia increases and it is an exothermic reaction.</em>
Answer: Le Chatleir Principle
Explanation: The answer of this question can be easily explanied through the Le Chatleir Principle which states that In order to maintain the equilibrium of the reaction, the stress applied to that particular direction will move the equilibrium to the opposite direction in which the stress has been applied.
The given reaction is -
If the amount of the oxygen is reduced to half and is being doubled, then the reaction will move in froward direction that is a rightward shift. Same situation will arise in option c and d.
If the amount of nitrogen monoxide is reduced to half or being doubled, the reaction will move towards backward direction that is a leftward reaction.