Answer:
A. K = 59.5
Explanation:
Hello there!
In this case, since this reaction seems to start moving leftwards due to the fact that neither A nor Y are present at equilibrium, we should rewrite the equation:
3C (g) + D (g) <-- --> 2A (g) + Y (g)
Thus, the equilibrium expression is:
![K^{left}=\frac{[A]^2[Y]}{[C]^3[D]}](https://tex.z-dn.net/?f=K%5E%7Bleft%7D%3D%5Cfrac%7B%5BA%5D%5E2%5BY%5D%7D%7B%5BC%5D%5E3%5BD%5D%7D)
Next, according to an ICE table for this reaction, we find that:
![[A]=2x](https://tex.z-dn.net/?f=%5BA%5D%3D2x)
![[Y]=x](https://tex.z-dn.net/?f=%5BY%5D%3Dx)
![[C]=0.651M-3x](https://tex.z-dn.net/?f=%5BC%5D%3D0.651M-3x)
![[D]=0.754M-x](https://tex.z-dn.net/?f=%5BD%5D%3D0.754M-x)
Whereas x is calculated by knowing that the [C] at equilibrium is 0.456M; thus:

Next, we compute the rest of the concentrations:
![[A]=2(0.065M)=0.13M](https://tex.z-dn.net/?f=%5BA%5D%3D2%280.065M%29%3D0.13M)
![[Y]=0.065M](https://tex.z-dn.net/?f=%5BY%5D%3D0.065M)
![[D]=0.754M-0.065M=0.689M](https://tex.z-dn.net/?f=%5BD%5D%3D0.754M-0.065M%3D0.689M)
Thus, the equilibrium constant for the leftwards reaction is:

Nonetheless, we need the equilibrium reaction for the rightwards reaction; thus, we take the inverse to get:

Therefore, the answer would be A. K = 59.5.
Regards!
Answer:
The answer to your question is letter C.
Explanation:
Reaction
Potassium hydroxide = KOH
Barium chloride = BaCl₂
Potassium chloride = KCl
Barium hydroxide = Ba(OH)₂
KOH + BaCl₂ ⇒ KCl + Ba(OH)₂
Reactant Elements Products
1 K 1
1 Ba 1
2 Cl 1
1 H 2
1 O 2
The reaction is unbalanced
2KOH + BaCl₂ ⇒ 2KCl + Ba(OH)₂
Reactant Elements Products
2 K 2
1 Ba 1
2 Cl 2
2 H 2
2 O 2
Now, the reaction is balanced
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.