Newton's 2nd law of motion: Force = (mass) x (acceleration)
Divide each side by (mass) : Acceleration = (force) / (mass)
Acceleration of the truck = (4,200 N) / (2,000 kg) = 2.1 m/s²
Answer:
10 km/h
Explanation:
Before calculating the average speed, we need to convert the time taken for the trip from minutes to hours. Since 1 hour cointains 60 minutes, we have:
Karen's average speed is given by:
where
d = 5 km is the distance covered
t = 0.5 h is the time taken for the trip
Substituting into the equation, we find
Answer:
a) v2=4147.72 m/s
b) stotal=5.53x10^6 m
Explanation:
a) the length from the center of the earth is equal to:
L1=1x10^6+((6.37/2)x10^6)=4.18x10^6 m
the velocity is 5.14 km/s=5.14x10^3 m/s
the farthest distance is equal to:
L2=2x10^6+((6.37/2)x10^6)=5.18x10^6 m
As the angular momentum is conserved, we have to:
I1=I2
m*L1*v1=m*L2*V2, where m is the mass of satelite
clearing v2:
v2=(L1*V1)/L2=(4.18x10^6*5.14x10^3)/5.18x10^6=4147.72 m/s
b) Using the Newton 3rd law:
vf^2=vi^2+2as
where:
a=g=9.8 m/s^2
vf=0
vi=5.14 km/s
s=?
Clearing s:
s=(vf^2-vi^2)/(2g)=((0-(5.14x10^3)^2)/(2*9.8)=1.35x10^6 m
the total distance is equal to:
stotal=s+L1=1.35x10^6+4.18x10^6=5.53x10^6 m
Answer:
20 m
Explanation:
Initial potential energy = final kinetic energy
mgh = 1/2 mv²
gh = 1/2 v²
h = v² / (2g)
Given v = 20 m/s and g = 10 m/s²:
h = (20 m/s)² / (2 × 10 m/s²)
h = 20 m
