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disa [49]
2 years ago
14

At this rate, what fraction of its mass would io lose in 4. 5 billion years?.

Physics
1 answer:
Pie2 years ago
4 0

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Given that:

Io loses about a ton (1000 kilograms) of sulfur dioxide per second to Jupiter's magnetosphere.

In 4.5 billion years, amount of mass lost = 1000 kg/s * (4.5 * 10⁹ * 365 * 60 60 * 24) = 1.41912 * 10¹⁷ kg.

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

Find out more on Equation at: brainly.com/question/13763238

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A circular steel wire 3.00 mm long must stretch no more than 0.25 cmcm when a tensile force of 780 NN is applied to each end of
fgiga [73]

Minimum diameter is required for the wire is 1.2X10⁻³m.

Tensile force, which consists of tensile stress and tensile strain, is the stretching force exerted on the material. This indicates that the forces are attempting to stretch the material that is subject to the force since it is under tension.

Given;

Tensile force (ft) = 780 N

length (l) = 3.00 mm

change in length (Δl) = 0.25 cm

determine the strain ε = Δl/l

determine the stress σ = Eε = E(Δl/l)

determine the cross-sectional area A = f/σ = ft/EΔl

determine the diameter d = 2\sqrt{} \frac{A}{\pi } = 2\sqrt{} \frac{ft}{EXΔlX\pi }

take Young's modulus for steel E=200 GPa, Substitute the values,

d = \sqrt[2]{\frac{x780X2}{y200X10^{9} X 0.0025\pi } } = 1.2X10⁻³

minimum diameter is required for the wire is 1.2X10⁻³m.

Learn more about the Tensile force with the help of the given link:

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I understand that the question you are looking for is "A circular steel wire 3.00 cm long must stretch no more than 0.25 cm when a tensile force of 780 N is applied to each end of the wire. What minimum diameter is required for the wire?"

4 0
2 years ago
In a study conducted by a University of Illinois researcher, the football team at Unity High School in Tolono, IL was equipped f
Angelina_Jolie [31]

The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s

<h3>How do I determine the duration (i.e time)?</h3>

Impulse is defined as the change in momentum of an object. It is expressed as:

Impulse = change in momentum

Impulse = final momentum – Initial momentum

Impule = m(v - u)

Impulse = force × time

Impulse = Ft

Thus,

Ft = m(v - u)

Where

  • F is the force
  • t is the time
  • m is the mass
  • u is the initial velocity
  • v is the final velocity

Now, we can obtain the duration (i.e time) of the impact. Details below:

  • Force (F) = 1770 N
  • Initial velocity = 2.09 m/s
  • Mass (m) = 4.12 Kg
  • Final velocity = 0 m/s
  • Duration (t) =?

Ft = m(v + u) since the collision came to a stop

1770 × t = 4.12 × (0 + 2.09)

1770 × t = 4.12 × 2.09

Divide both sides by 1770

t = (4.12 × 2.09) / 1770

t = 0.005 s

Thus, the duration is 0.005 s

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6 0
1 year ago
The Balmer series is formed by electron transitions in hydrogen that
yulyashka [42]

Answer:

b. end on the n = 2 shell.

Explanation:

When hydrogen atoms move from higher energy level to lower energy level then it shows spectral lines and these lines are known as Balmer series. The only four lines are visible and other liens are not in the visible range.

The Balmer series formed by hydrogen electron and it ends when n = 2.

Therefore the answer is b.

b. end on the n = 2 shell.

8 0
3 years ago
21 of 35 Review A friend of yours is loudly singing a single note at 401 HzHz while racing toward you at 23.0 m/sm/s on a day wh
Ipatiy [6.2K]

Answer:

The frequency of the sound note as heard = 429 Hz

Explanation:

The frequency of sound waves as heard from a distance for a sound wave coming towards one at v₀ m/s and whose real frequency is f₀ is given by

+f = f₀/[1 - (v₀/v)]

+f = frequency of sound as heard from the distance away = ?

f₀ = real frequency of sound = 401 Hz

v₀ = velocity at which the sound source is moving towards the reference point = 23.0 m/s

v = velocity of sound waves = 343 m/s

+f = 401/[1 - (23/343)]

+f = 429 Hz

5 0
3 years ago
Bill Nye- Static Electricity Answer Key?
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3 years ago
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