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disa [49]
2 years ago
14

At this rate, what fraction of its mass would io lose in 4. 5 billion years?.

Physics
1 answer:
Pie2 years ago
4 0

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Given that:

Io loses about a ton (1000 kilograms) of sulfur dioxide per second to Jupiter's magnetosphere.

In 4.5 billion years, amount of mass lost = 1000 kg/s * (4.5 * 10⁹ * 365 * 60 60 * 24) = 1.41912 * 10¹⁷ kg.

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

Find out more on Equation at: brainly.com/question/13763238

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MATHPHYS PLEASE HELP
solmaris [256]

Explanation:

Momentum is mass times speed.

p = mv

a) p = (1500 kg) (25.0 m/s) = 37,500 kg m/s

b) p = (40,000 kg) (1.00 m/s) = 40,000 kg m/s

The truck has more linear momentum.

Momentum in the y direction:

pᵧ = (1500 kg) (25.0 m/s) = 37,500 kg m/s

Momentum in the x direction:

pₓ = (1500 kg) (15.0 m/s) = 22,500 kg m/s

Total linear momentum:

p² = pₓ² + pᵧ²

p² = (22,500 kg m/s)² + (37,500 kg m/s)²

p = 43,700 kg m/s

3 0
3 years ago
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How are kinetic energy potential energy and thermal energy in a substance related?​
asambeis [7]

The energy associated with an object's motion is called kinetic energy. ... This is also called thermal energy – the greater the thermal energy, the greater the kinetic energy of atomic motion, and vice versa.

3 0
3 years ago
What is a analogy for transition metals
Ganezh [65]

<em>A simple metallic band model is proposed for the transition metal mono antimonides, by analogy to the transition metals.</em>

6 0
3 years ago
A 5000-kg freight car runs into a 10,000-kg freight car at rest. They couple upon collision and move with a speed of 2 m/s. What
Vitek1552 [10]

Answer:

C) 6 m/s

Explanation:

Given that

m₁=5000 kg

The initial velocity of 5000 kg car =u₁

m₂=10,000 kg

The initial velocity of 10000 kg car =u₂ = 0 m/s

After collision the final speed of the both car,v = 2 m/s

There is no any external force on the system that is why linear momentum will be conserved.

Linear momentum P = m v

m₁u₁ + m₂u₂ = (m₂ + m₁) v

5000 x u₁ + 10000 x 0 = (5000 + 10000) x 2

5000 x u₁ = 15000 x 2

5 x u₁ = 15 x 2

u₁ = 6 m/s

Therefore the answer is C.

C) 6 m/s

4 0
3 years ago
A ship, carrying freshwater to a desert island in the caribbean, has a horizontal cross-sectional area of 2800 m2 at the waterli
Alex17521 [72]
<span>Due that we already know the horizontal cross-sectional area of the ship, which is 2800 m2 and we are going to understand that value keeps constant for the whole 9.5 of height of the ship from the waterline till the new waterline after unloading, then we just need to calculate the volume as follows: V = A * H , where V is volume, A is area and H is height V= 2,800 * 9.5 = 26,600 m3 So this volum of 26,600 cubic meters is the volum of freshwater delivered in the island.</span>
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