The fourth term of (a+b)^5 is 10a^2b^3.
For a=w, b=-4z, this is
.. 10*(w)^2*(-4z)^3
.. = -640w^2*z^3
9/343
is the correct answer
mark me as the brainliest
Answer:
<em>Numbers: 6 and -2</em>
Step-by-step explanation:
<u>Equations</u>
This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.
However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:
![x+y=4\qquad\qquad [1]](https://tex.z-dn.net/?f=x%2By%3D4%5Cqquad%5Cqquad%20%5B1%5D)
![x.y=-12\qquad\qquad [2]](https://tex.z-dn.net/?f=x.y%3D-12%5Cqquad%5Cqquad%20%5B2%5D)
Solving [1] for y:

Substituting in [2]

Operating:

Rearranging:

Solving with the quadratic formula:

With a=1, b=-4, c=-12:



The solutions are:


This confirms the preliminary results.
Numbers: 6 and -2
Answer:
C) 9
Step-by-step explanation:
54 = 2 x 3 x 3 x 3
81 = 3 x 3 x 3 x 3
common factor of 54 and 81 = 3 x 3 = 9
Answer: 9
Given:
O is the midpoint of line MN
OM = OW
To prove: OW = ON
<u>Statement</u> <u>Reason</u>
1> OM = OW -------------------------> Given
2> OM = ON ---------------------------> O is the midpoint of line MN
i.e Point O bisects line MN
3> OM = OW --------------------------> From statement <1>
4> ON = OW -------------------------> OM = ON (Statement <2>)
OW = ON
<u>proved!!</u>