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KiRa [710]
2 years ago
12

A rocket carrying a satellite is accelerating straight up from the earth’s surface. At 1.15 s after liftoff, the rocket clears t

he top of its launch platform, 63 m above the ground. After an additional 4.75 s, it is 1.00 km above the ground. Calculate the magnitude of the average velocity of the rocket for (a) the 4.75-s part of its flight and (b) the first 5.90 s of its flight.
Physics
1 answer:
yarga [219]2 years ago
8 0

Answer:

197.263157895 m/s

169.491525424 m/s

Explanation:

x Denotes position

t Denotes time

Average velocity is given by

v_a=\dfrac{x_2-x_1}{t_2}\\\Rightarrow v_a=\dfrac{1000-63}{4.75}\\\Rightarrow v_a=197.263157895\ m/s

The average velocity is 197.263157895 m/s

v_a=\dfrac{x_2-x_1}{t_2}\\\Rightarrow v_a=\dfrac{1000-0}{5.9}\\\Rightarrow v_a=169.491525424\ m/s

The average velocity is 169.491525424 m/s

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In the chemical formula for an ionic compound, which item is written first?
tatuchka [14]

Explanation:

C,

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5 0
2 years ago
what is the ratio of ey,final, the maximum value of the y-component of the electric field immediately following the last polariz
OleMash [197]

That ratio is 2 .

<h3>What is ratio?</h3>

A ratio is the  comparison of the  two numbers bydivision.

Taking the first two outputs, or the  -1/8 and -1/4, we can divide not the second one by the first one to find the

ratio:

-1/4-1/8

When dividing fractions, we multiply by the reciprocal:

-1/4x-8/1

To multiply fractions, multiply straight across:

(-1x-8)/(4x1) 8/4=2

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8 0
1 year ago
A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are
Irina-Kira [14]

If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

<h3>Laws of electrical attraction</h3>

This states that

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Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

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4 0
1 year ago
hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check
leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

F=I(L\times B)

or

F=ILB\ sin\theta

Where

\theta is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

  1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
  2. .The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
  3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
7 0
3 years ago
The index of refraction of Sophia's cornea is 1.387 and that of the aqueous fluid behind the cornea is 1.36. Light is incident f
shtirl [24]

Answer:

17.85°

Explanation:

To find the angle to the normal in which the light travels in the aqueous fluid you use the Snell's law:

n_1sin\theta_1=n_2sin\theta_2

n1: index of refraction of Sophia's cornea = 1.387

n2: index of refraction of aqueous fluid = 1.36

θ1: angle to normal in the first medium = 17.5°

θ2: angle to normal in the second medium

You solve the equation (1) for θ2, next, you replace the values of the rest of the variables:

\theta_2=sin^{-1}(\frac{n_1sin\theta_1}{n_2})\\\\\theta_2=sin^{-1}(\frac{(1.387)(sin17.5\°)}{1.36})=17.85\°

hence, the angle to normal in the aqueous medium is 17.85°

7 0
3 years ago
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