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aleksandrvk [35]
2 years ago
12

A bag contains 2 black balls, 4 yellow balls and 4 white balls. Event A is defined as drawing a white ball on the first draw and

event B is defined as drawing a black ball on the second draw. If two balls are drawn from the bag, one after the other and not replaced, what is P(B|A) expressed in simplest form? A. B. C. D.
Mathematics
1 answer:
arsen [322]2 years ago
8 0

Answer: P(B|A)=\dfrac{4}{9}

Step-by-step explanation:

Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.

Event A is defined as drawing a white ball on the first draw.

Event B is defined as drawing a black ball on the second draw.

P(B|A) is expressed as the conditional probability of occurring B given that A.

i.e. it is the probability of happening B where A is already happended.

If a white ball is drawn at first, then the number of black ball(4) remains unchanged but the total number of balls (10) will become 9.

Probability=\dfrac{Number\ of \ favorable \ outcomes}{Total\ outcomes}

Then, P(B|A)=\dfrac{4}{9}

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4 0
3 years ago
I need help asappppppppppppp
svetoff [14.1K]

Answer: Choice [D] - "power of a power" ✅

Step-by-step explanation:

Hii, do you need to know which law you should use to simplify \sf\bigg(x^4\bigg)^9?

No problem!

The law we will use here is "power of a power".

What "power of powers" means is we raise a power to a power, which is exactly what we do here: We raise x^4 to the power of 9. To simplify our expression, we multiply the powers. (\boldsymbol{4\cdot9})

So the right answer is: Choice [D] - "Power of a power"

The simplified answer is \LARGE\boldsymbol{x^{4\cdot9}=x^{36}}

Voila! There's our answer, cheers!

--

Hope that this helped! Best wishes.

\it Reach\;far.\;Aim\;high.\;Dream\;big.}

--

7 0
1 year ago
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Juli2301 [7.4K]

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Hope it helps :-)

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