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aleksandrvk [35]
3 years ago
12

A bag contains 2 black balls, 4 yellow balls and 4 white balls. Event A is defined as drawing a white ball on the first draw and

event B is defined as drawing a black ball on the second draw. If two balls are drawn from the bag, one after the other and not replaced, what is P(B|A) expressed in simplest form? A. B. C. D.
Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer: P(B|A)=\dfrac{4}{9}

Step-by-step explanation:

Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.

Event A is defined as drawing a white ball on the first draw.

Event B is defined as drawing a black ball on the second draw.

P(B|A) is expressed as the conditional probability of occurring B given that A.

i.e. it is the probability of happening B where A is already happended.

If a white ball is drawn at first, then the number of black ball(4) remains unchanged but the total number of balls (10) will become 9.

Probability=\dfrac{Number\ of \ favorable \ outcomes}{Total\ outcomes}

Then, P(B|A)=\dfrac{4}{9}

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A point is reflected across the x-axis. The new point is (7.5,6). What is the distance between these two points?
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For each value of y, determine whether it is a solution to -2y+75-5.<br> Is it a solution?
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• No

• Yes

• Yes

• No

Step-by-step explanation:

To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.

-2y +7≤ -5

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Divide by -2 on both sides:

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This means that the solution can be 6 or greater than 6.

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Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.

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