Answer:
V= 14.2m/s
Explanation:
We know that acceleration= dv/dt
So 16m/s²=dv/ dt = v dv/ds
So this wil be
Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]
So 16[s (3/2)/3/2] at ( s,3) = v²/2
At s= 6m
So v² = 64/3( 6^1.5-3^1.5)
= 14.2m/s
If the hypothesis is tested extensively and if competing hypothesis are eliminated. Pretty much your hypothesis has to be tested many times and precisely accurate each time.
1. The speed is at a constant rate same with the acceleration and velocity
2. When there getting close to the top there speed, acceleration, and velocity all start to decrease
3. The speed and acceleration and velocity all on the way down drastically increase number
hope I helped
5m
Explanation:
Given parameters:
Energy = 35J
Force on object = 7N
Unknown:
Distance moved = ?
Solution:
The energy on the car will cause the car to do work . When work is done, a force moves a body in particular distance. We can see that energy and force are related:
Energy = force x distance
Distance = 
Inputting the parameters:
Distance = 
= 5m
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Work done brainly.com/question/9100769
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