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stealth61 [152]
3 years ago
12

Explain the law of conservation of energy then give an example that shows the slot to be true in your example explain where ther

e is potential energy and where there is kinetic energy also explain if any energy is lost to friction
Physics
1 answer:
Orlov [11]3 years ago
3 0
<h2>Answer:</h2>

<em><u>The energy of a system always remains constant as it can be converted from one type two another type. It can never be lost or created.</u></em>

<h3>Explanation:</h3>

Lets take an example of the boy riding a bicycle.

The boy is using the biochemical energy in his body to run the pedals up and down in a cycle form.

The biochemical energy is converted into the potential energy in the pedal.

As the pedal moves, it gives energy to move the wheels of the cycle and consequently the cycle will move forward.

Hence the potential energy is converted into the kinetic energy.

If the road is not clear, a lot of energy is needed to move the wheels or cycle as compared to clear road. Because some of the energy will be converted into heat during friction.

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A 1300 kg steel beam is supported by two ropes. (Figure
Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

  • the net horizontal force acting on the beam is

R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0

where R_1,R_2 are the magnitudes of the tensions in ropes 1 and 2, respectively;

  • the net vertical force acting on the beam is

R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0

where m=1300\,\rm kg and g=9.8\frac{\rm m}{\mathrm s^2}.

Eliminating R_2, we have

\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2

R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2

-R_1 \sin(50^\circ) = -\dfrac{mg}2

R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}

Solve for R_2.

\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0

\dfrac{R_2}2 = -mg\cot(110^\circ)

R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}

8 0
1 year ago
Kara is writing a science-fiction story. In the story, Earth no longer experiences day and night.
Ludmilka [50]

Answer:

C. She should get the Earth spinning on its axis again.

Explanation:

The Earth experiences day and night because of its spinning on its own axis.

If Kara's science-fiction story doesn't have the Earth spinning on its own axis, then the Earth will not experience day and night and hence Kara should incorporate this idea into his story.

6 0
3 years ago
Read 2 more answers
the pressure difference between an oil and water pipe is measured by double fluid manometer as shown in figure below for the giv
Ahat [919]
The answer above me is correct
8 0
3 years ago
a car with a mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve h
melisa1 [442]
In the given problem, we say various information's that are going to help us reach the ultimate answer to the question. Let us first write the information's that have been presented in front of us.
Mass of the car = 2000 kg
Velocity of the car = 25 m/s^2
Radius of the circle = 80 m
Now we already know the equation for calculating the centripetal force and that is
Centripetal Force = [mass * (velocity)^2]/Radius
                            = [2000 * (25)^2]/80
                            = (2000 * 625)/80
                            = 1250000/80
                            = 15625
So the centripetal force on the car is 15625 Newtons
  
4 0
3 years ago
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Which of the following will cause acceleration?
mixas84 [53]
The correct answer is C.
7 0
3 years ago
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