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UkoKoshka [18]
3 years ago
11

A man stands still on a moving walkway that is going at a speed of 0.2 m/s to

Physics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

0.2 m/s east

Explanation:

mark as brainlyest

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The skateboard stops after covering some distance bwhich law of newton is it ?
MrRa [10]

Friction... Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force

Means it will keep going until acted on by an outside force, in this case friction

6 0
3 years ago
Explain how heat is related to temperature and thermal energy...
daser333 [38]

Answer:

Thermal energy is directly related to heat because thermal energy is how heat is transfered.

5 0
3 years ago
A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change
Daniel [21]

Answer:

389 kg

Explanation:

The computation of mass is shown below:-

T = 2\pi \sqrt{\frac{m}{k} }

Where K indicates spring constant

m indicates mass

For the new time period

T^' = 2\pi \sqrt{\frac{m'}{k} }

Now, we will take 2 ratios of the time period

\frac{T}{T'} = \sqrt{\frac{m}{m'} }

\frac{1.50}{2.00} = \sqrt{\frac{0.500}{m'} }

0.5625 = \sqrt{\frac{0.500}{m'} }

m' = \frac{0.500}{0.5625}

= 0.889 kg

Since mass to be sum that is

= 0.889 - 0.500

0.389 kg

or

= 389 kg

Therefore for computing the mass we simply applied the above formula.

7 0
3 years ago
Who created a steel plow
Brut [27]
John Deere created steel plow
8 0
3 years ago
Read 2 more answers
A new interstate highway is being built with a design speed of 120 km/h. For one of the horizontal curves, the radius (measured
nikklg [1K]

Answer:

28.79%

Explanation:

Given

Design Speed, V = 120km/h = 33.33m/s

Radius, R = 300m

Side Friction, Fs = 0.09

Gravitational Constant = 9.8m/s²

Using the following formula, we'll solve the required rate of superelevation.

e + Fs = V²/gR where e = rate

e = V²/gR - Fs

e = (33.33)²/(9.8 * 300) - 0.09

e = 0.287853367346938

e = 28.79%

Hence, the required rate of superelevation for the curve is calculated as 28.79%

4 0
3 years ago
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