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3 years ago

Which jet stream flows around the sub-tropical high pressure systems and advects moisture along its poleward periphery?

Physics

1 answer:

stich3 [128]3 years ago

4 0

Answer:

polar is your answer

Explanation:

Polar jet stream

One factor that contributes to the creation of a concentrated polar jet is the undercutting of sub-tropical air masses by the more dense polar air masses at the polar front. This causes surface low pressure and higher pressure at altitude.

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A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 2.3 cm from the axis of rotation. (a) Calcul

VLD [36.1K]

Answer:

a) $a_{r} = 0.275\,\frac{m}{s^{2}}$ , b) $\mu_{s} = 0.028$ , c) $\mu_{s} = 0.036$

Explanation:

a) The linear acceleration of the watermelon seed is:

$a_{r} = \omega^{2}\cdot r$

$a_{r} = \left[\left(33\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\right]^{2}\cdot (0.023\,m)$

$a_{r} = 0.275\,\frac{m}{s^{2}}$

b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:

$\Sigma F = \mu_{s}\cdot m\cdot g = m\cdot a$

$a = \mu_{s}\cdot g$

$\mu_{s} = \frac{a}{g}$

$\mu_{s} = \frac{0.275\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.028$

c) Angular acceleration experimented by the turntable is:

$\alpha = \frac{\omega-\omega_{o}}{\Delta t}$

$\alpha = \frac{3.456\,\frac{rad}{s}-0\,\frac{rad}{s} }{0.36\,s}$

$\alpha = 9.6\,\frac{rad}{s^{2}}$

The tangential acceleration experimented by the watermelon seed is:

$a_{t} = \left(9.6\,\frac{rad}{s^{2}} \right)\cdot (0.023\,m)$

$a_{t} = 0.221\,\frac{m}{s^{2}}$

The linear acceleration experimented by the watermelon seed is:

$a = \sqrt{a_{t}^{2}+a_{r}^{2}}$

$a = \sqrt{\left(0.221\,\frac{m}{s^{2}} \right)^{2}+\left(0.275\,\frac{m}{s^{2}} \right)^{2}}$

$a = 0.353\,\frac{m}{s^{2}}$

The minimum coefficient of static friction is:

$\mu_{s} = \frac{0.353\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.036$

4 0

3 years ago

A horse slows from a velocity of 9.5 m/s to 5.5 m/s over a distance of 32 m. Find time.

lesya [120]

Answer:

Explanation:

Finding time= t=change in velocity or distance/acceleration

so 32/9.5-5.5

32/4

6 0

4 years ago

Why do plants not need digistive system

WINSTONCH [101]

Humans need a digestive system to do cellular respiration, which produces energy used for growth and movement.

Plants do not need one as they make their own energy through photosynthesis. The process produces glucose, which is a form of energy for the plants.

4 0

3 years ago

Read 2 more answers

A Ferris wheel has radius 5.0 m and makes one revolution every 8.0 s with uniform rotation. A person who normally weighs 670 N i

DaniilM [7]

Answer:

The apparent weight of the person as she pass the highest point is $N = 458.8 \ N$

Explanation:

From the question we are told that

The radius of the Ferris wheel is $r = 5.0 \ m$

The period of revolution is $T = 8.0 \ s$

The weight of the person is $W = 670 \ N$

Generally the speed of the wheel is mathematically represented as

$v = \frac{2 \pi r}{T }$

substituting values

$v = \frac{2 * 3.142 * 5}{8 }$

$v = 3.9 3 \ m/s$

The apparent weight (the normal force exerted on her by the bench) at the highest point is mathematically evaluated as

$N = mg - \frac{mv^2}{r}$

Where m is the mass of the person which is mathematically evaluated as

$m = \frac{W}{g}$

substituting values

$m = \frac{670}{9.8}$

$m = 68.37 \ kg$

$N = 68.37 * 9.8 - \frac{68.37 * {3.93}^2}{5}$

$N = 458.8 \ N$

5 0

3 years ago

What is the relationship between an objectâ€™s temperature and its heat?

Over [174]

Answer:

Explanation:

Heat and temperature are related to each other, but are different concepts. Heat is the total energy of molecular motion in a substance while temperature is a measure of the average energy of molecular motion in a substance. ... Temperature does not depend on the size or type of object

3 0

3 years ago