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3 years ago

Which jet stream flows around the sub-tropical high pressure systems and advects moisture along its poleward periphery?

Physics

1 answer:

stich3 [128]3 years ago

4 0

Answer:

polar is your answer

Explanation:

Polar jet stream

One factor that contributes to the creation of a concentrated polar jet is the undercutting of sub-tropical air masses by the more dense polar air masses at the polar front. This causes surface low pressure and higher pressure at altitude.

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An object is placed 100 cm in front of a diverging lens of focal length -25cm. A converging lens of focal length 33 1/3 cm is pl

bagirrra123 [75]

We use 1/o + 1/i = 1/f where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, 1/ 100 + 1 / i = - 1 /25 
i = - 20 cm 

For the case of the problem,

o = (20 + 30) = 50 cm 

f = 33.33. Using 1 / i + 1 / o = 1/f , i = 100 cm 

M = magnification = - i / o 

m1 = -(-20)/100 = 20/100 = 0.2 

m2 = -100/50 = -2 

M = m1*m2 = -2 x 0.2 = -0.4.

8 0

3 years ago

Mars, which has a radius of 3.4 × 106 m and a mass of 6.4 × 1023 kg, orbits the Sun, which has a mass of 2.0 × 1030 kg at a dist

Elena L [17]

Answer:

Tangential speed of Mass revolution is greater

Explanation:

In the above question, we are given the following values:

Radius of Mars = 3.4 × 10^6 m

Mass of Mars = 6.4 × 10^23 kg

Mass of the sun = 2.0 × 10^30 kg at a distance of 2.3 × 10^11m.

Mar’s revolution around the sun = 687 days.

Time of Revolution = 24 hours and 37 minutes to complete one revolution.

Step 1

Find the tangential speed of rotation of Mars

Rotation of Mars = 2 × π × r

Radius of Mars = 3.4 × 10^6 m

Rotation of Mars = 2 × π × 3.4 × 10^6 m

Rotation of Mars = 21362830.044m

= 21.4 × 10^6 m

Tangential Speed of rotation for Mars = Rotation of Mars/ time

Time = 24 hrs 37 minutes

Converting to seconds = 88620s

Tangential Speed of rotation = 21.4 × 10^6 m/ 88620s

= 241.48047845m/s

= 241.5 m/s

Step 2

revolution of Mars = 2 × π × d

d = 2.3 × 10^11m.

= 2 × π × 2.3 × 10^11m = 1.45 × 10^12m

Revolution of Mars = 687 days

Converting 687 days to seconds = 59356800s

Tangential Speed of Revolution of Mars = Revolution of Mars/ times

Tangential Speed of Revolution = 1.45 × 10^12m/595356800s

Tangential Speed of Revolution = 24420m/s

Comparing the Tangential Speed of Rotation with the Tangential speed of Revolution, we can see the GREATER ONE IS THE TANGENTIAL SPEED OF REVOLUTION.

8 0

3 years ago

Read 2 more answers

A stuntman drives a car off the edge of a rooftop and jumps mid-air to reach his safety net.

lara31 [8.8K]

Answer:

Acceleration is towards the center of the earth

Explanation:

khan

7 0

2 years ago

What is the magnitude of the electrostatic force

ozzi

The electron charge is called the Elementary Charge, given by:

$e=1.6*10^{-19}$

The Eletrostatic Force bewteen two changes is giver by Coulomb Law:

$F= \frac{Qqk}{d^2}$

Substituing the unknowns, we have:

$F= \frac{(1.6*10^{-19})^2}{(10^{-8})^2} \\ F=(1.6*10^{-11})^2 \\ \boxed {F=2.56*10^{-22}N}$

If you notice any mistake in my english, please let me know, because i am not native.

5 0

3 years ago

Read 2 more answers

131_I_53 is an artificially made radioactive isotope of iodine, produced during the operation of nuclear power plants and the de

cricket20 [7]

Answer:

one beta particle

Explanation:

Since the atomic number of 131_I_53 increases by one to 131_Xe_54, we have the release of a beta particle since only a beta particle can cause a change in atomic number without a change in mass number. Since a beta particle is one electron, ₋₁⁰e, our nuclear equation is

¹³¹I₅₃ → ¹³¹X₅₄ + ₋₁⁰e

The atomic and mass numbers on both sides are balanced

mass number 131 = 131 + 0 = 131

atomic number 53 = 54 - 1 = 53

Thus a beta particle is emitted

4 0

3 years ago