The answer is going to be A.
Answer: 1800 L
Explanation:
Given that,
Original pressure of gas (P1) = 180 kPa
Original volume of gas (V1) = 1500 L
New pressure of gas (P2) = 150 kPa
New volume of gas (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P1V2
180 kPa x 1500 L = 150 kPa x V2
270000 kPa•L = 150 kPa•V2
Divide both sides by 150 kPa
270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa
1800L = V2
Thus, the new volume of the gas is 1800 liters.
Can’t understand question. I don’t know Spanish
Taking into account the reaction stoichiometry, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
4 Al + 3 O₂ → 2 Al₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Al: 4 moles
- O₂: 3 moles
- Al₂O₃: 2 moles
The molar mass of the compounds is:
- Al: 27 g/mole
- O₂: 32 g/mole
- Al₂O₃: 102 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Al: 4 moles ×27 g/mole= 108 grams
- O₂: 3 moles ×32 g/mole= 96 grams
- Al₂O₃: 2 moles ×102 g/mole= 204 grams
<h3>Mass of Al₂O₃ formed</h3>
The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

<u><em>mass of Al₂O₃= 102 grams</em></u>
Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.
Learn more about the reaction stoichiometry:
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The chemical reaction would most likely be written as follows:
A + B = AB
We cannot simply use the usual method of converting grams to moles since we do not have any idea on what are the identities of A and B. The only method we could use is to use the law of conservation of mass where mass inflow in a process should be equal to the mass out in the process. The total inflow of mass would be the mass of A and B and the outflow would be the product AB.
mass of A + mass of B = mass of AB
10.0 g A + 10.0 g B = mass of AB
mass of AB = 20.0 g