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NARA [144]
3 years ago
8

EASY BUT I STILL NEED HELP

Chemistry
2 answers:
Jet001 [13]3 years ago
4 0

Answer:

If I’m correct it is 3

Explanation:

finlep [7]3 years ago
3 0

Answer: 3 they move more freely since water is a liquid and ice is a solid in a solid molecules are more compact and cannot move around much but in a liquid it moves more freely than it would in a solid.

Explanation:

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811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of
Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

  • Provided heat (Q): 811.68 J
  • Mass of the metal (m): 95 g
  • Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0
3 years ago
You apply 100.0 n of force to a machine. The machine applies 20.0 n of force to the load. What is the mechanical advantage of th
MAXImum [283]
Answer: I Think Its 5.00
7 0
3 years ago
HELP PLEASE!!!!!
Mashutka [201]

Answer:

National fire protection Association

Explanation:

the nfpa is a global self funded nonprofit orgnazation establised in 1896 devoted to eliminating death injury protery loss and ecomomic loss due to fire and electrical hazards

4 0
3 years ago
Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc
densk [106]
<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

                                     = 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

                              = 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

            = (15 g ÷ 17.42 g) × 100 %

            = 86.11%

7 0
3 years ago
3. How many formula units of NaOH are in 0.87 moles?
Lady_Fox [76]

Answer: 1 mole of H2O= about 1/3 of a cup (18 mL). It is helpful ... 6.02 x 1023 H2O molecules. = 6.02 x 1023 NaCl formula unit. 1 mole C. 1 mole H2O. 1 mole

Explanation:

5 0
2 years ago
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