<u>Answer:</u> The volume of stock NaCl solution needed is 23 mL
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock NaCl solution
are the molarity and volume of diluted NaCl solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock NaCl solution needed is 23 mL
Answer:
The new volume at -29°C and 432 torr is 6.51 L
Explanation:
Step 1: Data given
Initial volume of CO = 4.63 L
Initial temperature = 296.0 K
Initial pressure = 737 torr = 737/760 = 0.9697 atm
Step 2: Calculate the new volume
(P1*V1)/T1 = (P2*V2)/T2
V2 = (P1V1*T2) / (T1*P2)
⇒ with P1 = the initial pressure = 0.9697 atm
⇒ with V1 = the initial volume = 4.63 L
⇒ with T1 = The initial temperature = 296.0 K
⇒ with T2 = the new temperature = -29.0 + 273 = 244 K
⇒ with P2 = the new pressure = 432/760 = 0.5684 atm
V2 = (P1V1/T1) * (T2/P2)
V2 = 6.51 L
The new volume at -29°C and 432 torr is 6.51 L
Answer:
82.04g
Explanation:
To solve this problem, you need to find the molar mass of HCl, which is the sum of the molar mass of H plus the molar mass of Cl. The molar mass of H is 1.008g/mol while the molar mass of Cl is 35.45g/mol. Thusly the molar mass of HCl is 36.458g/mol. You have 2.25 moles of HCl, so multiply the number of moles by the molar mass to get the mass in g. In this case it is 2.25mol * 36.458g/mol = 82.04g.
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Sulphur, Chlorine, Argon, Silicon and Aluminium are all in the same period as Phosphorus.
Whiteish silver
shiny
ductile
conductor
metal
left
