Answer:
33.6 Ns backward.
Explanation:
Impulse: This can be defined as the product of force and time. The S.I unit of impulse is Ns.
From Newton's second law of motion,
Impulse = change in momentum
I = mΔv................................. Equation 1
Where I = impulse, m = mass of the skater, Δv = change in velocity = final velocity - initial velocity.
Given: m = 28 kg, t = 0.8 s, Δv = -1.2-0 = -1.2 m/s (Note: the initial velocity of the skater = 0 m/s)
Substituting into equation 1
I = 28(-1.2)
I = -33.6 Ns
Thus the impulse = 33.6 Ns backward.
Answer:
Emergency Room or a Clinic
Explanation:
The Emergency Room if in a hospital. A Clinic may also see patients without insurance, but they're not on Emergency Room grounds.
Answer:Increase in the entropy of the universe are the result of chemical reactions
Explanation:
The second law tells about the quality of energy such that any isolated system tends to become more disordered. Any natural Process occurring on its own is irreversible and entropy is increasing for that process.
The entropy of the Universe is increasing which is the result of chemical reactions. Any chemical reaction which increases the number of gas molecules will generate more entropy. Entropy in simple meaning is the order of randomness.
Answer:
The angular acceleration of CD player is
.
Explanation:
Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.
It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :

So, the angular acceleration of CD player is
.
Answer:
a)
0.245 m/s
b)
0.904 m
Explanation:
a)
= speed of duck ahead of wave
= speed of surface wave = 0.32 m/s
T = time for paddling = 1.6 s
d = spacing between the waves = 0.12 m
speed of duck ahead of wave is given as
=
- 
= 0.32 - 
= 0.245 m/s
b)
= speed of wave behind the duck
speed of wave behind the duck is given as
=
+ 
= 0.32 + 0.245
= 0.565 m/s
D = spacing between the crests
spacing between the crests is given as
D =
T
D = (0.565) (1.6)
D = 0.904 m