Answer:
Dimension of cardboard is 22 m by 16 m
Explanation:
Given that,
Area = 352 cm²
Side of each square cutting from corner = 2 cm
Volume of box = 432 cm³
Let the two sides are x and y.
The area of the rectangular piece is
![xy=352](https://tex.z-dn.net/?f=xy%3D352)
-------- (1)
The volume of the rectangular piece
![2(x-4)(\dfrac{352}{x}-4)=432](https://tex.z-dn.net/?f=2%28x-4%29%28%5Cdfrac%7B352%7D%7Bx%7D-4%29%3D432)
![x^2-38x+352=0](https://tex.z-dn.net/?f=x%5E2-38x%2B352%3D0)
![(x-16)(x-22)=0](https://tex.z-dn.net/?f=%28x-16%29%28x-22%29%3D0)
x=16,22
Put the value of x in the equation (I)
For x = 16
For x = 22
Dimension of cardboard is 22 m by 16 m
Answer:
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Explanation:
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Explanation:
Answer:
Part a)
![T = 42 N](https://tex.z-dn.net/?f=T%20%3D%2042%20N)
Part b)
![v_f = 11.8 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2011.8%20m%2Fs)
Part c)
![t = 1.7 s](https://tex.z-dn.net/?f=t%20%3D%201.7%20s)
Part d)
![F = 159.7 N](https://tex.z-dn.net/?f=F%20%3D%20159.7%20N)
Explanation:
Part a)
While bucket is falling downwards we have force equation of the bucket given as
![mg - T = ma](https://tex.z-dn.net/?f=mg%20-%20T%20%3D%20ma)
for uniform cylinder we will have
![TR = I\alpha](https://tex.z-dn.net/?f=TR%20%3D%20I%5Calpha)
so we have
![T = \frac{1}{2}MR^2(\frac{a}{R^2})](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B2%7DMR%5E2%28%5Cfrac%7Ba%7D%7BR%5E2%7D%29)
![T = \frac{1}{2}Ma](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B2%7DMa)
now we have
![mg = (\frac{M}{2} + m)a](https://tex.z-dn.net/?f=mg%20%3D%20%28%5Cfrac%7BM%7D%7B2%7D%20%2B%20m%29a)
![a = \frac{mg}{(\frac{M}{2} + m)}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bmg%7D%7B%28%5Cfrac%7BM%7D%7B2%7D%20%2B%20m%29%7D)
![a = \frac{15 \times 9.81}{(6 + 15)}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B15%20%5Ctimes%209.81%7D%7B%286%20%2B%2015%29%7D)
![a = 7 m/s^2](https://tex.z-dn.net/?f=a%20%3D%207%20m%2Fs%5E2)
now we have
![T = \frac{12 \times 7}{2}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B12%20%5Ctimes%207%7D%7B2%7D)
![T = 42 N](https://tex.z-dn.net/?f=T%20%3D%2042%20N)
Part b)
speed of the bucket can be found using kinematics
so we have
![v_f^2 - v_i^2 = 2 a d](https://tex.z-dn.net/?f=v_f%5E2%20-%20v_i%5E2%20%3D%202%20a%20d)
![v_f^2 - 0 = 2(7)(10)](https://tex.z-dn.net/?f=v_f%5E2%20-%200%20%3D%202%287%29%2810%29)
![v_f = 11.8 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2011.8%20m%2Fs)
Part c)
now in order to find the time of fall we can use another equation
![v_f - v_i = at](https://tex.z-dn.net/?f=v_f%20-%20v_i%20%3D%20at)
![11.8 - 0 = 7 t](https://tex.z-dn.net/?f=11.8%20-%200%20%3D%207%20t)
![t = 1.7 s](https://tex.z-dn.net/?f=t%20%3D%201.7%20s)
Part d)
as we know that cylinder is at rest and not moving downwards
so here we can use force balance
![F = T + Mg](https://tex.z-dn.net/?f=F%20%3D%20T%20%2B%20Mg)
![F = 42 + (12 \times 9.81)](https://tex.z-dn.net/?f=F%20%3D%2042%20%2B%20%2812%20%5Ctimes%209.81%29)
![F = 159.7 N](https://tex.z-dn.net/?f=F%20%3D%20159.7%20N)
1)Typically, atom gain or lose electrons to achieve
I believe the correct answer from the choices listed is option C, a stable electron configuration
2)The formation of an ionic bond involves
I believe the correct answer is A, transfer of electrons since it is electrons that is involved in a chemical reaction.
Answer:
1)
Acceleration (a)=change in velocity/ change in time
Velocity (v)=90m/s
Time=0.0005s
a=90/0.0005
The acceleration =180000m/s^2 or 180km/s^2
Force = mass x acceleration
m=40g= 0.04kg
F= 0.04x 180000
F= 7200N or 7.2kN
Explanation: