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Serhud [2]
3 years ago
13

A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.3 m/s rel

ative to the ground.
Physics
1 answer:
Sonja [21]3 years ago
4 0

consider east-west direction along X-axis  and north-south direction along Y-axis

V_{ra} = velocity of migrating robin relative to air = 12 j m/s

(where "j" is unit vector in Y-direction)

V_{ag} = velocity of air relative to ground = 6.3 i m/s

(where "i" is unit vector in X-direction)

V_{rg} = velocity of migrating robin relative to ground = ?

using the equation

V_{rg} = V_{ra} + V_{ag}

V_{rg} = 12 j + 6.3 i

V_{rg} = 6.3 i + 12 j

magnitude : sqrt((6.3)² + (12)²) = 13.6 m/s

direction : tan⁻¹(12/6.3) = 62.3 deg north of east

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Explanation:

From the question we are told that

   The  diameter is  d =  12 \  cm  =  0.12 \ m

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       E =  \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 +  k^2 } } ]

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      E =  \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 +  (1.0*10^{-4})^2 } } ]

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