Can anyone help me with this question
1 answer:
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Answer:
a) 1. 1365 × 10⁻⁹N
b) 9.1862 × 10⁻⁴⁶N
c) 8.61 × 10⁻¹¹C/Kg
Explanation:
Ke = 8.99× 109 N.m2 / C2 , G = 6.67 × 10-11 N. m2 / kg2
a) F = Ke . q₁.q₂/r²
= (8.99× 109 N.m2 / C2 ) ×(1.60×10⁻¹⁹C)²/(4.50×10⁻¹⁰C)²
= 1. 1365 × 10⁻⁹N
b)
F = Gm₁m₂/r²
= (6.67× 10⁻¹¹)×(1.67×10⁻²⁷)²/(4.50×10⁻¹⁰)²
= 9.1862 × 10⁻⁴⁶N
The electric force is larger by 8.0497 ×10³⁷ times
c)
if Keq₁q₂/r² Gm₁m₂/r²,
with q₁=q₂ = q, and m₁ =m₂ = m
Then q/m = =
= 8.61 × 10⁻¹¹C/Kg
Answer:
I = 20 A
Explanation:
The question says that, "A load of 6,000 C is conducted through a cross section in 5 minutes. Determining-if a current is not correct, we will find the value of?"
We have,
Charge, q = 6,000 C
Time, t = 5 minutes = 300 s
We need to find the current. We know that, the charge flowing per unit time is equal to current. So,
So, the current flowing through the circuit is 20 A.