Explanation:
this is due to the roughness of the metal like you mentioned aluminum and iron are rough and don't provide a reflective surface as good as a mirror
One of the major effects of heat transfer is temperature change: heating increases the temperature while cooling decreases it. We assume that there is no phase change and that no work is done on or by the system. Experiments show that the transferred heat depends on three factors—the change in temperature, the mass of the system, and the substance and phase of the substance.
Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.
semiconductors ... silicon, germanium etc ...
Answer:
2H₂S + SO₂ —> 2H₂O + 3S
Explanation:
From the question given above, the following equation were obtained:
H₂S + SO₂ —> H₂O + S
The equation can be balance as illustrated below:
H₂S + SO₂ —> H₂O + S
There are 2 atoms of O on the left side and 1 atom on the right side it can be balance by writing 2 before H₂O as shown below:
H₂S + SO₂ —> 2H₂O + S
There are 2 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 2 before H₂S as shown below:
2H₂S + SO₂ —> 2H₂O + S
There are 3 atoms of S on the left side and 1 atom on the right side. It can be balance by writing 3 before S as shown below:
2H₂S + SO₂ —> 2H₂O + 3S
Now, the equation is balanced.!
