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77julia77 [94]
3 years ago
13

Is the topic of atoms and elements a branch of physics??

Physics
1 answer:
lara [203]3 years ago
8 0
It's chemistry because you talk about atoms that make up elements while in physics you go even smaller such as in quarks, leptons, and bosons, talking about elementary particles is particle physics
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Something that has many particles in a small space would have a ————- density
Diano4ka-milaya [45]

Answer:

a high density i believe

Explanation:

4 0
3 years ago
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Jada is rowing a boat across a river that has a current of 5 m/s in the ˆ j direction. Leanne, standing on the shore, observes J
olchik [2.2K]

Answer: d. 8.25 m/s

Explanation:

We are given that Current= 5 m/s in j direction

Velocity= 8 m/s i + 3 m/s j

Now, we have to find Jada's speed with respect to the water.

First we find Jada's velocity with respect to water

v= (8 i + 3 j) - (5 j)

v= 8i - 2 j

To find the speed, we take the magnitude of this velocity vector we have

|v|= \sqrt{(8)^2+(-2)^2}

|v|= \sqrt{68} = 8.246 m/s

which comes out to be around = 8.25 m/s

So option d is correct.

5 0
3 years ago
I will give brainliest
Inga [223]

Answer:

it has nucleus

Explanation:

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3 years ago
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A block of mass 0.510 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T
maria [59]

Answer:

x=0.46m, speed=7.9m/s

Explanation:

Using the concept of conservation of energy:

1. kinetic energy of mass m and velocity v: E_k=\frac{1}{2}mv^2

2. gravitational potential energy of mass m, grav. acc. g and height h: E_g=mgh

3. potential energy in a spring with spring constant k and displacement from equilibrium x: E_s=\frac{1}{2}kx^2

Calculating x:

\frac{1}{2}mv_a^2=\frac{1}{2}kx^2

x=\sqrt{\frac{m}{k}}v_a

Calculating the speed:

\frac{1}{2}mv_a^2 +mgh_a=\frac{1}{2}mv_b^2+mgh_b + W_{friction}

h_a=0, h_b=2R,W_{friction}=F_{friction}\times distance=7\pi R

\frac{1}{2}mv_a^2=\frac{1}{2}mv_b^2+2mgR+7\pi R

Solving for v_b:

v_b=\sqrt{v_a^2-4gR-14\pi\frac{R}{m}}

7 0
3 years ago
During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passe
arlik [135]

Answer:

F = 400 N

Explanation:

Given,

The acceleration of the car, a = 8 m/s²

The mass of the passenger, m = 50 Kg

The force acting on a body is equal to the product of the mass and its acceleration

                                    F = m x a   newtons

Substituting the given values in the above equation,

                                     F = 50 Kg x 8 m/s²

                                        = 400 N

Hence, the force exerted by the person on the seat belt is, F = 400 N

7 0
3 years ago
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