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kupik [55]
3 years ago
5

PLS HELP MEEMEE In June, the average temperature at the North Pole is 59° F. In December, the average temperature at the North P

ole is 69° F colder than June's average temperature.
In February, the average temperature at the North Pole is ½ as cold December's average temperature.



What is the average temperature, in degrees Fahrenheit, at the North Pole in Febru


I WILL MARK BRAINLIST IF WORK IS SHOWEN
Mathematics
2 answers:
shutvik [7]3 years ago
5 0

Answer:

59-69=-10,     1/2 of 10=5

so the answer is 5 degrees Fahrenheit

Step-by-step explanation:

The 59-69 came from December being 69 degrees less than junes temperature, and the 1/2 of 10 came from February being half as cold as December's temperature.

Hope this helped!

iVinArrow [24]3 years ago
5 0

Answer:

February's Average Temperature 5º

Step-by-step explanation:

December Temp is 69º colder than June so add June's Temp and December's together 69º - 59º  = 10º

December's Temperature is 10º so if February is ½ as cold then we mutiply ½ by 10º which is 5º.  (You could also divide 10 by 2)

Frebruary's Temp is 5º

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Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now =  L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle =  800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) =  800 - 400 = 400 meters

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4 years ago
Write each fraction as a decimal 4/50
Len [333]
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3 years ago
Solve the equation with special factors. (Please show all steps) <br> 4p^4 - 25p^2 = -16p^2
daser333 [38]

Answer:

The solutions can be p=3/2 or p=-3/2

Step-by-step explanation:

4p^4 - 25p^2 + 16p^2 = 0

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3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.
valentinak56 [21]

                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

\rightarrow Now, subtract 3x on both sides:-

                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

    \Large\text{$y=-\displaystyle\frac{3}{2}x +2$}

\rule{300}{3}

Now, let's find the equation of the line that's parallel to the given line.

Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

\Large\text{$-\displaystyle\frac{3}{2}$}

Now let's write the equation in point-slope form:-

\hookrightarrow\sf{y-y_1=m(x-x_1)}

Replace numbers with letters, as follows:-

\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}

The equation above is the equation in point-slope form.

Incase you need it converted to slope intercept form, refer to the steps below ~

Multiply -3/2 times x and -4:-

\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}

Now, Add 5 on both sides:-

\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

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