Answer:
FALSE
Since 0.385 < 0.526, the value for week 3 is accepted.
Explanation:
Qexp = (|Xq - Xₙ₋₁|)/w
where Xq is the suspected outlier; Xₙ₋₁ is the next nearest data point; w is the range of data
First, the data are arranged in decreasing order, from highest to lowest:
3. 5.6
2. 5.1
8. 5.1
1. 4.9
6. 4.9
5. 4.7
7. 4.5
4. 4.3
Xq = 5.6; Xₙ₋₁ = 5.1; w = 5.6 - 4.3 = 1.3
Qexp = (|5.6 - 5.1|)/1.3 = 0.385
From tables, at 95% confidence level, for n = 8, Qcrit = 0.526
Since 0.385 < 0.526, the value for week 3 is accepted.
Answer:
a)
⇒
⇒
b)
⇒
⇒
Explanation:
A)
Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:
⇒
The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:
⇒
b)
Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:
⇒
Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:
⇒
Answer :
(1) The frequency of photon is, 
(2) The energy of a single photon of this radiation is 
(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
Explanation : Given,
Wavelength of photon =
(1 m = 100 cm)
(1) Now we have to calculate the frequency of photon.
Formula used :

where,
= frequency of photon
= wavelength of photon
c = speed of light = 
Now put all the given values in the above formula, we get:


The frequency of photon is, 
(2) Now we have to calculate the energy of photon.
Formula used :

where,
= frequency of photon
h = Planck's constant = 
Now put all the given values in the above formula, we get:


The energy of a single photon of this radiation is 
(3) Now we have to calculate the energy in J/mol.



The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
610.864 Energy result in kilojoules:
Answer:
I think your answer is either b or c but I think b is more likely to be your answer