Answer:
In the civil litigation process what will happen to Bobby Jones are in four stages which are Inquiry and Pleading, Discovery, Motion Practice and Negotiation and Trial and Appeal.
Explanation:
Four steps are involved in the process of civil litigation stated as follows:
In this staged a complaint is first issued against Bobby Jones by the ABC Corporation which elaborates on the offence and also points out the financial compensation for the damaged or problems caused.
Inquiry and Pleading: The first step or phase is the inquiry and pleading.
In this staged a complaint is first issued against Bobby Jones by the ABC Corporation which elaborates on the offence and also points out the financial compensation for the damaged or problems caused.
(2) Discovery: This is where the various parties gives an effort to get more information as possible
(3) Motion Practice and Negotiation: This occurs prior to trial when bobby files motion to challenge the complaint issued against him.
(4)Trial and Appeal: The last stage is the trial and appeal. this occurs when the previous steps has failed.
In this step the trial is held, both Bobby and ABC Corporations seeks judgement from the judge and the judge issues the jury to put in the final verdict. If both parties are not satisfied with judgement received, they can appeal to a higher court to review the verdict or decision.
Answer:
Debit Work in Process Inventory $113,000;
Debit Factory Overhead $18,000.
Explanation:
$82,000 of direct labor related is associated with assembly department.
and $31,000 of labor not directly related to the product but related to the Assembly Department as a whole . Therefore its a indirect cost means overhead
$18,000 of labor services this cost is not associated with the product, but indirectly incurred in making material to the final product. hence this cost is also part of indirect cost.
Answer:
least waiting time = 18 mins
Explanation:
given as per question we know that 2nd bus start 10 min early than 1st bus
and both time frequency same = 30 min
1st bus time take = 1 hr 12 mins
and 2nd bus get waiting time 30 min - (10 + 12)
that is = 8 mins
so
we can say time arrival time for 1st bus = 8:32 and 9:02 and 9:32
by adding 30 mins
and
departure time for 2nd bus = 8:40 and 9:10 and 9:40
same like that 3rd bus leave every hour
and
service start on hour clock , a 10 mins early is = 7:10 am and 9 am
frequency of either half or 1 hour
so 2nd bus takes = 2 hour 40 mins
so waiting time is 60 - (10 - 40) = 10 min or 10 + 30 = 40 mins
so 1st bus waiting time is 8 mins so it take least time 10 mins for 2nd bus waiting time
as that
least waiting time = 8 + 10
least waiting time = 18 mins
