Perhaps the most important use of tin, historically, has been to make bronze — an alloy of copper and tin or other metals — that changed civilization by ushering in the Bronze Age. People began making or trading for bronze tools and weapons at different times, depending on geography, but the Bronze Age is commonly accepted to have started around 3300 B.C. in the Near East.
Answer:
S = 1.1 × 10⁻⁹ M
Explanation:
NaCl is a strong electrolyte that dissociates according to the following expression.
NaCl(aq) → Na⁺(aq) + Cl⁻(aq)
Given the concentration of NaCl is 0.15 M, the concentration of Cl⁻ will be 0.15 M.
We can find the molar solubility (S) of AgCl using an ICE chart.
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
I 0 0.15
C +S +S
E S 0.15+S
The solubility product (Ksp) is:
Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S (0.15 + S)
If we solve the quadratic equation, the positive result is S = 1.1 × 10⁻⁹ M
Answer:
mL of NaOH required =29.9mL
Explanation:
Let us calculate the moles of vitamin C in the tablet:
The molar mass of Vitamin C is 176.14 g/mole
Thus we need same number of moles of NaOH to reach the equivalence point.
For NaOH solution:
Answer:
100% pea plants will be with green pod and with round seeds.
Explanation:
As per the question given, a homozygous pea plant having green pod (gg) and round seeds (WW) is crossed with a pea plant having homozygous green pod (gg) and heterozygous round seeds(Ww). A pea plant homozygous for green pod and round seeds (ggWW) will produce one type of gametes having alleles (gW), whereas, a pea plant homozygous for green pod and heterozygous for round seeds(ggWw) will produces two type of gametes having alleles gW and gw. On crossing, phenotypically, they will produce all pea plants with green pod and round seeds. But genotypically, 50% of green pod pea plants with homozygous round seeds and 50% of green pod pea plants with heterozygous round seeds.
Explanation:
A. Force = Mass x Acceleration