All categories

3 years ago

Calculate the molar solubility of silver chloride in 0.15 M sodium chloride.

Chemistry

2 answers:

vova2212 [387]3 years ago

7 0

Answer:

S AgCl = 1.066 E-9 M

Explanation:

NaCl(s) → Na+(aq) + Cl-(aq)

0.15 M 0.15 M 0.15 M

AgCl(s) → Ag+(aq) + Cl-(aq)

S S S + 0.15

∴ Ksp AgCl = 1.6 E-10 = [Ag+]*[Cl-]

⇒ Ksp = 1.6 E-10 = ( S )*( S + 0.15 )

⇒ S² + 0.15S - 1.6 E-10 = 0

⇒ S = 1.066 E-9 M

Alex777 [14]3 years ago

6 0

Answer:

S = 1.1 × 10⁻⁹ M

Explanation:

NaCl is a strong electrolyte that dissociates according to the following expression.

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

Given the concentration of NaCl is 0.15 M, the concentration of Cl⁻ will be 0.15 M.

We can find the molar solubility (S) of AgCl using an ICE chart.

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I 0 0.15

C +S +S

E S 0.15+S

The solubility product (Ksp) is:

Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S (0.15 + S)

If we solve the quadratic equation, the positive result is S = 1.1 × 10⁻⁹ M

You might be interested in

. Write the balanced equation, then outline the steps necessary to determine the information requested in each of the following:

mafiozo [28]

Answer:

See explanation

Explanation:

a) The equation of the reaction is;

2Na + Cl2 ------>2NaCl

Number of moles of sodium = 10g/23 g/mol = 0.43 moles

If 2 moles of sodium reacts with 1 mole of Cl2

0.43 moles reacts with 0.43 * 1/2 = 0.215 moles of Cl2

Mass = 0.215 moles of Cl2 *71 g/mol = 15.265 g

b) Equation of the reaction;

HgO -> Hg + O2

1.252 moles of HgO 1.252/32 gmol = 0.039 moles

1 mole of HgO yields 1 mole of oxygen hence

0.039 moles of HgO yields 0.039 moles of oxygen

Mass of oxygen = 0.039 moles * 32 g/mol = 1.248 g

c) Equation of the reaction;

2NaNO3 -----> 2NaNO2 + O2

Number of moles of 128 g of oxygen = 128g/32 g/mol = 4 moles

2 moles of NaNO3 yields 1 mole of oxygen

x moles of NaNO3 yields 4 moles of oxygen

x = 8 moles of NaNo3

Mass of NaNO3 = 8 * 85 g/mol = 680 g of NaNo3

6 0

2 years ago

A student measures a mass of an 8cm3 block of brown sugar to be 19.9G. what is the density of the brown sugar?

Naily [24]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{19.9}{8} \\ = 2.4875$

We have the final answer as

Hope this helps you

3 0

3 years ago

Why is all matter affected by gravity

Vlad [161]

Answer:

Explanation:

Gravity:

It is the force by which the elements of matter pulls together.

Explanation:

The gravity is depend upon the mass of matter. The more mass of object the more will be the gravitational force.

The earth is most heavier than all other matter that's why all matter pulls towards the earth.

For example;

when we walk on the earth, it pull us. Our mass is less as compared to the earth that's why we fall back on the earth instead of moving upward because our pull is negligible because of greater difference in masses. The earth mass is very high.

The gravitational force is inversely proportional to the square distance of interacting objects.

As the two objects are more distance apart from each other the less will be the gravitational force.

5 0

3 years ago

Select the correct answer.

oksian1 [2.3K]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

What is the conjugate acid of HCO3- ?OH-H2CO3CO32-H2OH3O+

adell [148]

<u>Answer:</u> The conjugate acid of $HCO_3^-$ is $H_2CO_3$

<u>Explanation:</u>

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base.
A base is defined as a substance which accepts protons and thus forming conjugate acid.

To form a conjugate acid of $HCO_3^-$ , this compound will accept one proton to form $H_2CO_3$

The chemical equation for the formation of conjugate acid follows:

$HCO_3^-+H^+\rightarrow H_2CO_3$

The conjugate acid formed is named as carbonic acid.

Hence, the conjugate acid of $HCO_3^-$ is $H_2CO_3$

5 0

3 years ago