2 years ago

( urgent help needed!! 50pts + brainliest )

Chemistry

2 answers:

Ivanshal [37]2 years ago

5 0

Answer:

Thorium-234 option a .......

Marizza181 [45]2 years ago

4 0

238 4 234

U --> α + Th

92 2 90

The answer is A Thorium.

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The. bond dissociation enthalpies of the H-H bond and the H-Cl bond are 435 kJ mol^-1 and 431 kJ mol^-1, respectively. The ΔHfO

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The bond dissociation energy of the Cl - Cl bond is -958 kJ mol^-1.

<h3>What is the dissociation enthalpy?</h3>

Given that;

H-H bond energy = 435 kJ mol^-1

H-Cl bond energy = 431 kJ mol^-1

ΔHfO of HCL(g) = -92kJ mol^-1

Bond dissociation enthalpy of the Cl-Cl bond = x

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x = -92 - (435 + 431)

x = -958 kJ mol^-1

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A solution is made by adding 29.1 mL of concentrated perchloric acid ( 70.5 wt% , density 1.67 g/mL ) to some water in a volumet

Lera25 [3.4K]

Answer:

The concentration of the solution is 1.364 molar.

Explanation:

Volume of perchloric acid = 29.1 mL

Mass of the solution = m

Density of the solution = 1.67 g/mL

$m=1.67 g/mL\times 29.1 mL=48.597 g$

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Mass of perchloric acid in 48.597 solution :

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So, volume of the final solution = 250 mL = 0.250 L (1 mL = 0.001 L)

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$=\frac{0.3410 mol}{0.250 L}=1.364 M$

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